All categories

3 years ago

Question 1:

2 answers:

8 0

Question 1:
Given that the points (-7, 6), (3, 6), (3, -6), and (-7, -6) are vertices of a rectangle, how much longer is the length than the width?
A)1 unit
☆☆☆☆☆☆☆☆B) 2 units (12-10=2)
C) 3 units
D) 4 units

question 2:
Given that the points (-2, 10), (5, 10), (5, 1), and (-2, 1) are vertices of a rectangle, how much longer is the length than the width?
A) 1 unit
☆☆☆☆☆☆☆☆B) 2 units (9-7=2)
C) 3 units
D) 4 units

lara31 [8.8K]3 years ago

3 0

Question 2- two units

You might be interested in

Help me with my math**50 pts** i mark brainliest**

xenn [34]

Answer:

3) Reflexive Property

4) SAS

Step-by-step explanation:

1. The Reflexive Property states that: a quantity is congruent (equal) to itself.

Example: a = a
In this case, it could be seen as ST ≅ ST because they have/are the same side(s).

1. SAS theorem states that: two triangles are equal if two sides and the angle between those two sides are equal.

Example: RST ≅ UTS (both have S and T)
Can be seen as RST ≅ UST as well to make their similarity more evident.

2. Because it is given that RS ≅ UT and RT ≅ US, and it includes the same 2 lines being equal as given/said, RST ≅ UTS because of SAS (theorem).

4 0

4 years ago

<img src="https://tex.z-dn.net/?f=%5Csqrt%7Bx%5E%7B2%7D%20%2B5x%2B3%7D%20%2B2x%5E%7B2%7D%20%2B10x-15%3D0" id="TexFormula1" title

Anettt [7]

<h3>Factor</h3><h3>√x²+5x+3+2x²+10x-15=0</h3><h3>√x²+2x²+5x+10x+3-15=0</h3><h3>√3x²+15x-12=0</h3><h3>√3x²+(3(5x)+3×-4=0</h3><h3>√3(x²+5x)+3×-4=0</h3><h3>√3(x²+5x-4)=0</h3><h3> </h3>

please mark this answer as brainlist

8 0

3 years ago

The Sahara Desert has an area of approximately 9,400,400 km2. While estimates of its average depth vary, they center around 150

dolphi86 [110]

Answer:

$1.128048 \times 10^{25}$ grains of sand are in the Sahara Desert

Step-by-step explanation:

Given :

The Sahara Desert has an area of approximately 9,400,400 sq.km.

Depth = 150 m

To Find :Approximately how many grains of sand are in the Sahara Desert?

Solution:

Area of Sahara desert = 9,400,400 sq.km.

$1 km^2 = 1000000 m^2$

So, $9,400,400 km^2 = 1000000 \times 9400400 m^2$

$9,400,400 km^2 =9.4004 \times 10^{12}m^2$

Volume of sand = $Area \times depth$

= $1.41006\times 10^{15} m^3$

$1 m ^3 = 1000000 cm^3$

So, $1.41006\times 10^{15} m^3 = 1.41006\times 10^{15} \times 1000000cm^3$

$1.41006\times 10^{15} m^3 =1.41006 \times 10^{21}cm^3$

1 cubic cm holds grains of sand = 8000

$1.41006 \times 10^{21}cm^3$ holds grains of sand = $1.41006 \times 10^{21} \times 8000$

= $1.128048 \times 10^{25}$

Hence $1.128048 \times 10^{25}$ grains of sand are in the Sahara Desert

7 0

3 years ago

Compute the standard error for sample proportions from a population with proportion p= 0.55 for sample sizes of n=30, n=100 and

Pani-rosa [81]

Given Information:

Population proportion = p = 0.55

Sample size 1 = n₁ = 30

Sample size 2 = n₂ = 100

Sample size 3 = n₃ = 1000

Required Information:

Standard error = σ = ?

Answer:

$\sigma_1 = 0.091$

$\sigma_2 = 0.050$

$\sigma_3 = 0.016$

Step-by-step explanation:

The standard error for sample proportions from a population is given by

$\sigma = \sqrt{\frac{p(1-p)}{n} }$

Where p is the population proportion and n is the sample size.

For sample size n₁ = 30

$\sigma_1 = \sqrt{\frac{p(1-p)}{n_1} }$

$\sigma_1 = \sqrt{\frac{0.55(1-0.55)}{30} }$

$\sigma_1 = 0.091$

For sample size n₂ = 100

$\sigma_2 = \sqrt{\frac{p(1-p)}{n_2} }$

$\sigma_2 = \sqrt{\frac{0.55(1-0.55)}{100} }$

$\sigma_2 = 0.050$

For sample size n₃ = 1000

$\sigma_3 = \sqrt{\frac{p(1-p)}{n_3} }$

$\sigma_3 = \sqrt{\frac{0.55(1-0.55)}{1000} }$

$\sigma_3 = 0.016$

As you can notice, the standard error decreases as the sample size increases.

Therefore, the greater the sample size lesser will be the standard error.

8 0

4 years ago

Simplify the expression 9m-7m+2m

tatuchka [14]

Simplify step-by-step.

9m−7m+2m

=9m+−7m+2m

Combine Like Terms:

=9m+−7m+2m

=(9m+−7m+2m)

=4m

4 0

3 years ago