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3 years ago

The sum of a rational number and a rational number is sometimes rational

Mathematics

2 answers:

Nata [24]3 years ago

4 0

Answer:

The sum of a rational number and a rational number is ALWAYS rational

Step-by-step explanation:

N76 [4]3 years ago

3 0

Answer:

The sum of two rational numbers is rational. Here is one way to explain why it is true: Any two rational numbers can be written and , where are integers, and and are not zero. Multiplying or adding two integers always gives an integer, so we know that and are all integers.

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NO SCAM. PLEASE SHOW WORK. WILL GIVE BRAINLY TO CORRECT ANSWER.

sergeinik [125]

Answer:

$140$

Step-by-step explanation:

A regular polygon is a shape with equal sides and angles. Because of this, we can write the following equation to set two sides equal to each other:

$3a+b+3=2a+2b+6$

Solving, we will get a in terms of b:

$3a=2a+b+3,\\a=b+3$

Now we can substitute a for (b+3) into our equation:

$5a-2b+1=2a+2b+6,\\5(b+3)-2b+1=2(b+3)+2b+6,\\3b+16=4b+12,\\-b=-4,\\b=\boxed{4}$

Therefore, the length of each side of this polygon is $5(4+3)-2(4)+1=28$ .

Since the perimeter of the polygon consists of all five sides, the perimeter is:

$p=28\cdot 5 =\boxed{140}$

6 0

3 years ago

Read 2 more answers

Rani deposited AED 12000 for 3 years at the rate of 5 percent per annum. Calculate the simple interest and amount at the end of

Luda [366]

Answer:

the principal and the amount is 1,800 and 13,800 respectively

Step-by-step explanation:

The computation of the simple interest and amount for the end of the 3rd year is shown below:

Simple interest is

= Principal × rate of interest × time period

= 12,000 × 5% × 3 years

= 1,800

Now the amount is

= 12,000 + 1,800

= 13,800

hence, the principal and the amount is 1,800 and 13,800 respectively

7 0

2 years ago

What are the solutions to the quadratic equation -2x^2 + 6x + 3 = 0?

mario62 [17]

For this, we will be using the quadratic formula, which is $x=\frac{-b+/-\sqrt{b^2-4ac}}{2a}$ , with a=x^2 coefficient, b=x coefficient, and c = constant. Our equation will look like this: $x=\frac{-6+/-\sqrt{6^2-4*(-2)*3}}{2*(-2)}$

Firstly, solve the multiplications and the exponents: $x=\frac{-6+/-\sqrt{36+24}}{-4}$

Next, do the addition: $x=\frac{-6+/-\sqrt{60}}{-4}$

Next, your equation will be split into two: $x=\frac{-6+\sqrt{60}}{-4},\frac{-6-\sqrt{60}}{-4}$ . Solve them separately, and your answer will be $x=-0.436,3.436$