There are 138 different combinations that they could end up first, second, and third.
Answer: 0.444225
Step-by-step explanation:
Given : The total number of tickets = 50
Number of tickets are randomly sampled without replacement =6
Since the order of selection is not important , so we use combinations.
Total number of ways to select 6 tickets = 
The number of winning tickets = 6
So, number of tickets that are not winning = 50-6=44
Number of ways of selecting zero winning numbers= 
Now , the probability of holding a ticket that has zero winning numbers out of the 6 numbers selected for the winning ticket out of the 50 possible numbers would be 

Hence, the required probability = 0.444225
Answer:
Option A.
Step-by-step explanation:
Let M be the milk per gallon.
C be the cookies per dozen.
B be the bundle (one gallon of milk and a dozen cookies ).
Milk can be sold by itself for a profit of $1.50 per gallon. Cookies can likewise be sold at a profit of $2.50 per dozen and bundle is sold for a profit of $3.00 per bundle.

We need to maximize the profits. So, our objective function is
Therefore, the correct option is A.
12/10 = 1 2/10 or 1 1/5
15/6 = 2 3/6 or 2 1/2.
To turn these fractions into mixed numbers you have to see how much times the denominator can go into the numerator and the amount of numbers left over. For 12/10, 10 can go into 12 1 time, so the whole number is 1. There is 2 numbers left over, so the numerator is 2 and you do not have to change the denominator. To simplify, divide the numerator and denominator by the highest number it can be divided to