All categories

2 years ago

I NEED HELP lol

Mathematics

1 answer:

Iteru [2.4K]2 years ago

8 0

Answer:

Step-by-step explanation:

must gain 10 yards

they lost 24 yards

gained 4

-24 + 4 = -20

they lost 10 more

- 20 -10 = -30

x + -30 = 10

x = 10 + 30

x = 40 yards

You might be interested in

55.405 greater than 55.045

Kobotan [32]

55.405 is bigger then 55.045

4 0

2 years ago

Read 2 more answers

Find f(1/3) if f(n)=3n

tia_tia [17]

F(n)=3n
f(1/3)=3(1/3)
f(1/3)=1

Hope I didn't mess up for your sake

8 0

2 years ago

write the logarithm as a sum or difference of logarithms. simplify each term as much as possible. log4(6ab)

Dominik [7]

The logarithm written as a sum of logarithm and simplified as much as possible is $\frac{1}{2} +log_{4 }3 + log_{4 }a + log_{4 }b$

<h3>Simplifying Logarithms</h3>

From the question, we are to write the given logarithm expression as a sum or difference of logarithms

The given logarithm is

$log_{4 }6ab$

This can be written as

$log_{4 }6 \times a \times b$

From one of the rules of logarithm, we have that

$log_{x }yz= log_{x }y + log_{x }z$

Thus,

$log_{4 }6 \times a \times b$ becomes

$log_{4 }6 + log_{4 }a + log_{4 }b$

This can be further simplified into

$log_{4 }3 \times 2 + log_{4 }a + log_{4 }b$

$log_{4 }3 + log_{4 }2 + log_{4 }a + log_{4 }b$

If desired, this can be further simplified into

$log_{4 }3 + log_{2^{2} }2 + log_{4 }a + log_{4 }b$

$log_{4 }3 + \frac{1}{2} log_{2}2 + log_{4 }a + log_{4 }b$

$log_{4 }3 + \frac{1}{2} (1)+ log_{4 }a + log_{4 }b$

$\frac{1}{2} +log_{4 }3 + log_{4 }a + log_{4 }b$

Hence, the logarithm written as a sum of logarithm and simplified as much as possible is $\frac{1}{2} +log_{4 }3 + log_{4 }a + log_{4 }b$

Learn more on Simplifying logarithms here: brainly.com/question/17851187

#SPJ1

8 0

1 year ago

I NEED HELP PLEASE, THANKS! :)

Aleonysh [2.5K]

but where is ur question ??????

5 0

2 years ago

Read 2 more answers

Jenny opened a package of screws quickly and many of them spilled on the floor. She needs to organize the fasteners according to

hichkok12 [17]

We have to compare diameters and arrange them in order smallest to greatest

We can see units for option A and B are in square inches so they represents area. So first we will find diameter from area using formula

$A = \pi r^{2}$

so for choice (A) area is given as $4.375 \times 10^{7}$ . So plug this in A place in formula and then solve for radius r

$4.375 \times 10^{7} = \pi r^{2}$

$\frac{4.375 \times 10^{7}}{\pi} = \frac{\pi r^{2}}{\pi}$

$1.393 \times 10^{7} } = r^{2}$

$\sqrt{1.393 \times 10^{7}} = \sqrt{r^{2}}$

3731.76 = r

So screw A will have
$diameter = 2 \times r = 2 \times 3731.76 = 7463.52$ inches

Similarly for choice (E) area is $1.428 \times 10^{1} = 14.28$
so again plug in formula

$A = \pi r^{2}$

$14.28 = \pi r^{2}$

$\frac{14.28}{\pi} = \frac{\pi r^{2}}{\pi}$

$4.5477 = r^{2}$

$\sqrt{4.5477} = \sqrt{r^{2}}$

2.13201 = r

So screw E will have
$diameter = 2 \times r = 2 \times 2.13201 = 4.26402$ inches

So diameters of all screws are as follows:

Screw A: 7463.52 inches
Screw B: 1.5 inches
Screw C: $1\frac{7}{8} = \frac{1\times 8+7}{8} = \frac{15}{8} = 1.875$ inches
Screw D: 0.25 inches
Screw E: 4.26402 inches

Comparing all numbers 7463.52, 1.5, 1.875, 0.25, 4.26402 we can see that smallest number is 0.25, then comes 1.5, then 1.875 and then 4.26402 and then 7463.52

So order from least to greatest will be screw D (0.25), B(1.5), C(1.875), E (4.26402), A (7463.52).

So thats the order D,B,C,E,A and the final answer

6 0

3 years ago

Read 2 more answers