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gregori [183]
3 years ago
13

Solve the formula for b2. Area of a trapezoid: A=12h(b1+b2)

Mathematics
2 answers:
Mkey [24]3 years ago
8 0

Answer:

A = (12h x b1) + (12h x b2)

A = 12hb1 + 12hb2

A - 12hb1 = 12hb1 - 12hb1 +12hb2

A - 12hb1 = 12hb2

(A - 12hb1) / (12h) = (12hb2) / (12h)

b2 = (A - 12hb1) / (12h)

Fittoniya [83]3 years ago
5 0

Answer:

b₂ = \frac{2A-hb_{1} }{h}

Step-by-step explanation:

A = \frac{1}{2} h(b₁ + b₂) ← multiply both sides by 2 to clear the fraction

2A = h(b₁ + b₂) ← distribute

2A = hb₁ + hb₂ ( subtract hb₁ from both sides )

2A - hb₁ = hb₂ ( divide both sides by h )

\frac{2A-hb_{1} }{h} = b₂

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Answer:

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Which one of these is a whole number?<br><br> a. 4/7<br> b.square root of 8<br> c.0<br> d.0.1
alina1380 [7]

Answer:

The answer is C. 0

5 0
3 years ago
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Based on Pythagorean identities, which equation is true? A. Sin^2 theta -1= cos^2 theta B. Sec^2 theta-tan^2 theta= -1 C. -cos^2
Arturiano [62]

Answer:

D

Step-by-step explanation:

our basic Pythagorean identity is cos²(x) + sin²(x) = 1

we can derive the 2 other using the listed above.

1. (cos²(x) + sin²(x))/cos²(x) = 1/cos²(x)

1 + tan²(x) = sec²(x)

2.(cos²(x) + sin²(x))/sin²(x) = 1/sin²(x)

cot²(x) + 1 = csc²(x)

A. sin^2 theta -1= cos^2 theta

this is false

cos²(x) + sin²(x) = 1

isolating cos²(x)

cos²(x) = 1-sin²(x), not equal to sin²(x)-1

B. Sec^2 theta-tan^2 theta= -1

1 + tan²(x) = sec²(x)

sec²(x)-tan(x) = 1, not -1

false

C. -cos^2 theta-1= sin^2

cos²(x) + sin²(x) = 1

sin²(x) = 1-cos²(x), our 1 is positive not negative, so false

D. Cot^2 theta - csc^2 theta=-1

cot²(x) + 1 = csc²(x)

isolating 1

1 = csc²(x) - cot²(x)

multiplying both sides by -1

-1 = cot²(x) - csc²(x)

TRUE

3 0
3 years ago
Fill in the missing numbers in this table NEED ASAP PLEASE ANYONE
Rashid [163]

Answer:

Step-by-step explanation:

add all divide by to total no.of value

64/4=16

mean=16

4 0
2 years ago
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nalin [4]

Answer:

20+4x

Step-by-step explanation:

Distributive property is quite easy to learn... its just multiplication in an easier form to visualize once you're used to using it.

To first start this problem you want to use the number 4 in the expression 4(5+x). You then want to multiply 4 by both terms inside of the parentheses. So you would do both 4*5 and 4*x. You would then get 20+4x because 4*5=20 and 4*x is just put together as 4x.

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3 years ago
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