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Ilia_Sergeevich [38]

3 years ago

7

The median of the data set is 18. What number is missing? 12,17, _ , 21,13,25

1 answer:

mash [69]3 years ago

6 0

Answer:

9

Step-by-step explanation:

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A deck of 40 cards contains 20 blue and 20 red cards. Each color has cards numbered 1 to 20.

FinnZ [79.3K]

Answer:

A red 5 is chosen from the deck. The card is put back into the deck and the a red card is chosen.

Step-by-step explanation:

An independent event is one whose outcome is not dependent on any other event. There are two types of cards in the deck. If a red card is selected it will be from the series 1 - 20, if the card is put back into deck and then again a red card is selected it will be again from the series 1 - 20. This is an independent event since its outcome is same irrespective of the events.

3 0

3 years ago

Read 2 more answers

Find the value of x and the measure of the missing angle

Dmitrij [34]

Answer:

the missing angle=85

x=95

Step-by-step explanation:

180-95=85

6 0

3 years ago

-15b^5+18b^3/3b<br> ??? Help

ioda

-15b^5+18b^3/3b

= -15b^5+ 6b^2

= 3b^2(-5b^3 + 2)

4 0

3 years ago

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IF 48% of the students in a class are girls:

EastWind [94]

The percentage is 52% and the fraction is 13/25

4 0

3 years ago

Arithmetic sequences et sn} be an arithmetic sequence that starts with an initial index of 0. The initial term is 3 and the comm

navik [9.2K]

Answer:

(a) The value of $s_z$ is (z+1)(3-z).

(b) The next term in the sequence is -2.

Step-by-step explanation:

(a)

It is given that arithmetic sequence that starts with an initial index of 0.

The initial term is 3 and the common difference is -2.

$a_0=3$

$d=-2$

We need to find the value of $s_z$ .

$s_z=\sum_{n=0}^{n=z}(a+nd)$

where, a is initial term and d is common difference.

$s_z=\sum_{n=0}^{n=z}(3-2n)$

The sum of an arithmetic sequence with initial index 0 is

$s_n=\frac{n+1}{2}[2a+nd]$

where, a is initial term and d is common difference.

Substitute n=z, a=3 and d=-2 in the above formula.

$s_z=\frac{z+1}{2}[2(3)+z(-2)]$

$s_z=\frac{z+1}{2}[2(3-z)]$

$s_z=(z+1)(3-z)$

Therefore the value of $s_z$ is (z+1)(3-z).

(b)

The given arithmetic sequence is

7, 4, 1, ...

We need to find the term in the sequence.

In the given arithmetic sequence the first term is

$a=7$

The common difference of the sequence is

$d=a_2-a_1\Rightarrow 4-7=-3$

The first term is 7 and common difference is -3.

Add common difference in last given term, i.e., 1, to find the next term of the sequence.

$1+(-3)=1-3=-2$

Therefore the next term in the sequence is -2.

3 0

4 years ago