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2 years ago

Write each fraction in its simplest form. 8 8 II 25

Mathematics

1 answer:

WINSTONCH [101]2 years ago

5 0

Answer:

$\frac{88}{5^{2} }$

Step-by-step explanation:

There are no fractions I am assuming the fraction is 88/25 which would be 88/5^2

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What is the thirty-second term of the arithmetic sequence -12, -7, -2, 3, ... ? Show your work.

anzhelika [568]

The thirty-second term is 143

Further explanation:

As it is already given that the given sequence is an arithmetic sequence

We have to find the common difference first

So,

$a_1=-12\\a_2=-7\\a_3=-2\\a_4=3$

$d=a_2-a_1=-7-(-12)=-7+12=5\\a_3-a_2=-2-(-7)=-2+7=5$

The common difference is 5.

And first term is -12

The explicit formula for arithmetic sequence is:

$a_n=a_1+(n-1)d\\Here,\\a_n\ is\ nth\ term\\a_1\ is\ first\ term\\d\ is\ common\ difference$

Putting the values in the formula

$a_n=-12+(n-1)(5)\\a_n=-12+5n-5\\a_n=-17+5n$

Putting n=32 in explicit formula

$a_{32}=-17+5(32)\\=-17+160\\=143$

The thirty-second term is 143

Keywords: Common difference, Arithmetic Sequence

Learn more about arithmetic sequence at:

#LearnwithBrainly

6 0

2 years ago

Find the missing terms of this geometric sequence. HELP PLEASE

patriot [66]

I can't help u with this but I can give the formula tn=t1+(n-1)+d

5 0

3 years ago

Sum of cubes: (a b)(a2 – ab b2) = a3 b3 Difference of cubes: (a – b)(a2 ab b2) = a3 – b3 Which products result in a sum or diffe

valentina_108 [34]

By comparing all the options with the formula of sum of cubes and difference of cubes we get that $(x+4)\left(x^{2}-4 x+16\right)$ is sum of cubes

<h3>What is formula of sum of cubes and difference of cubes?</h3>

Formula of sum of cubes and difference of cubes are following

$(a+b)(a^2 -ab +b^2) = a^3+ b^3 \\\\\\(a - b)(a^2+ ab+ b^2) = a^3 - b^3$

(a)

$(x-4) \left(x^{2}+4 x-16\right)\\=(x-4) \left(x^{2}+4 x-4^2\right)\\\\$

by comparison with formula we can say that this is neither sum or nor difference of cubes.

(b)

$(x-1)\left(x^{2}-x+1\right)\\=(x-1)\left(x^{2}-x+1^2\right)$

by comparison with formula we can say that this is neither sum nor difference of cubes.

(c)

$(x+1)(x-1)=x^{2}-1^{2}\\$

we can say that this is neither sum nor difference of cube as it's difference of squares.

(d)

$(x+4)\left(x^{2}-4 x+16\right)\\\\(x+4)\left(x^{2}-4 x+4^2\right)$

by comparison with formula this is equal to

$x^{3}+4^{3}\\$

Hence this is sum of cubes

(e)

$(x+4)\left(x^{2}+4 x+16\right)\\(x+4)\left(x^{2}+4 x+4^2\right)$

by comparison with formula we can say that this is neither sum nor difference of cubes.

By comparing all the options with the formula of sum of cubes and difference of cubes we get that $(x+4)\left(x^{2}-4 x+16\right)$ is sum of cubes

To know more about cubes visit: brainly.com/question/107100

8 0

1 year ago

Which arrangment shows 27/5,5 3/5, and 33/6 in order least to greatest

svetoff [14.1K]

5 3/5, 27/5, 33/6 , hope I helped lmk if I got it right

8 0

2 years ago

Are these answers correct

professor190 [17]

No you have to move the decimal place over 2 times to the left

7 0

2 years ago