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AveGali [126]
2 years ago
13

Help i don't know what the answer is ​

Mathematics
1 answer:
____ [38]2 years ago
3 0
The answer to that is -4!!
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(WILL DO BRAINLIST)
Lynna [10]
You have a function y= \dfrac{3}{2} \left(1+\sin  \left(\dfrac{2t+1}{2}\cdot \pi\right) \right).
Since the range of the function y=\sin x is [-1,1] you have that

-1\le \sin \left(\dfrac{2t+1}{2}\cdot \pi\right)\le 1 \\ 0\le 1+\sin \left(\dfrac{2t+1}{2}\cdot \pi\right) \le 2 \\ 0\le \dfrac{3}{2} \left(1+\sin \left(\dfrac{2t+1}{2}\cdot \pi\right) \right)\le 3.
Answer: The range of given function is [0,3] and the correct choice is C.
6 0
2 years ago
Welcome to Gboard clipboard, any text you copy will be saved here.​
Dafna11 [192]

Answer:

yooo i got the new rank im now expert :0

Step-by-step explanation:

XD

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