Answer:
The original duration of the tour is 18 days.
Step-by-step explanation:
Let
the number of days spent be T
Daily expenses be D
Initially ,
total tour expenses was 360
-------------(1)
If he extends his tour for 4 days, he has to cut down his daily expenses by dollar 3
---------------(2)
Expanding the eqaution(2)
DT-3D + 4T -12 = 360
Substituting the value of D
Solving the quadratic equation we get
T = 18 and T = -15
T is the number of gays and it cannot be negative , hence T is 18
Substituting in equation (1) we get
D = 20
Answer:
- 20
Step-by-step explanation:
Total Change in enrollment = - 60
Period of time at which change occurred = 3 years
Average change per year :
Total change in enrollment / period at which change occurred
= - 60 / 3
= - 20
Average change of - 20 enrollments per year
<em>The answer is Ms Hernandez can bring up to 6 people to the zoo.</em>
<em />
<em>x - the number of people that she can bring to the zoo</em>
<em>The parking will cost $7: a = 7</em>
<em>Admission tickets will cost $15.50 per person: b = 15.50x</em>
<em>She can spend on parking and admission tickets $100:</em>
a + b ≤ 100
a = 7
b = 15.50x
7 + 15.50x ≤ 100
15.50x ≤ 100 - 7
15.50x ≤ 93
x ≤ 93 / 15.50
x ≤ 6
Answer:
A
Step-by-step explanation:
See paper for order of operations
Answer:
The correct answer is C.
Step-by-step explanation:
In order to solve this problem, you need to simplify the equation by using a natural log (ln). This will cancel out the e and make it easy to solve.
e^(2x + 5) = 4 ----> Take the ln
lne^(2x + 5) = ln(4) ------> Simplify
2x + 5 = ln(4) ------> Subtract 5
2x = ln(4) - 5 -----> Divide by 2
x = [ln(4) - 5]/2
