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2 years ago

Celia bought a bag of 12 goldfish for $3 dollar sign. What is the cost of 1 goldfish?

Mathematics

1 answer:

Alchen [17]2 years ago

8 0

Celia bought a bag of 12 goldfish for $3 dollar.

Cost of 12 goldfish = $3
Cost of 1 goldfish = $3/12 = $1/4

= $0.25

<h3>The cost of 1 goldfish is $0.25.</h3>

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The estimated velocity v (in miles per hour) of a car at the end of a drag race is v=234 3√p/w (cube root) , where p is the hors

faltersainse [42]

Given that v=234 3√p/w (cube root)
where 
p is the horsepower of the car and
w is the weight (in pounds) of the car
v is the velocity in miles per hour

p = 1311 hp
w = 2744 lb
substitute the given value to the equation to solve for the velocity

v = 234 3√(1311 / 2744)
v = 183 miles per hour is the velocity of a car at the end of a drag race.

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3 years ago

Whats another way to write 171.9%

Nastasia [14]

$p\%=\frac{p}{100}\\\\171.9\%=\frac{171.9}{100}=\frac{171.9\cdot10}{100\cdot10}=\frac{1719}{1000}=\boxed{1\frac{719}{1000}=1.719}$

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3 years ago

(4y+5)(7y-3)= what is the solution to this problem

nikdorinn [45]

Answer:

all work is pictured/shown

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2 years ago

NEED HELP EDU!! WILL GIVE BRAINLEIST! which graph of the cube root function f(x)=^3 √x?

Luden [163]

Answer:

C. $f(x)=\sqrt[3]{-x} -1$

Step-by-step explanation:

Consider graph of the parent function (red curve in attached diagram)

$g(x)=\sqrt[3]{x}$

First, multiply it by -1 to get function

$h(x)=-\sqrt[3]{x}$

Then translate the graph of the function h(x) 1 unit down, then you'll get the function

$f(x)=-\sqrt[3]{x} -1\\ \\ \text{or}\\ \\f(x)=\sqrt[3]{-x} -1$

The graph of the function f(x) is represented by the blue curve in attached diagram

5 0

3 years ago

The distribution of weights for newborn babies is approximately normally distributed with a mean of 7.4 pounds and a standard de

blsea [12.9K]

Answer:

1. 15.87%

2. 6 pounds and 8.8 pounds.

3. 2.28%

4. 50% of newborn babies weigh more than 7.4 pounds.

5. 84%

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 7.4 pounds

Standard Deviation, σ = 0.7 pounds

We are given that the distribution of weights for newborn babies is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

1.Percent of newborn babies weigh more than 8.1 pounds

P(x > 8.1)

$P( x > 8.1) = P( z > \displaystyle\frac{8.1 - 7.4}{0.7}) = P(z > 1)$

$= 1 - P(z \leq 1)$

Calculation the value from standard normal z table, we have,

$P(x > 8.1) = 1 - 0.8413 = 0.1587 = 15.87\%$

15.87% of newborn babies weigh more than 8.1 pounds.

2.The middle 95% of newborn babies weight

Empirical Formula:

Almost all the data lies within three standard deviation from the mean for a normally distributed data.
About 68% of data lies within one standard deviation from the mean.
About 95% of data lies within two standard deviations of the mean.
About 99.7% of data lies within three standard deviation of the mean.

Thus, from empirical formula 95% of newborn babies will lie between

$\mu-2\sigma= 7.4-2(0.7) = 6\\\mu+2\sigma= 7.4+2(0.7)=8.8$

95% of newborn babies will lie between 6 pounds and 8.8 pounds.

3. Percent of newborn babies weigh less than 6 pounds

P(x < 6)

$P( x < 6) = P( z > \displaystyle\frac{6 - 7.4}{0.7}) = P(z < -2)$

Calculation the value from standard normal z table, we have,

$P(x < 6) =0.0228 = 2.28\%$

2.28% of newborn babies weigh less than 6 pounds.

4. 50% of newborn babies weigh more than pounds.

The normal distribution is symmetrical about mean. That is the mean value divide the data in exactly two parts.

Thus, approximately 50% of newborn babies weigh more than 7.4 pounds.

5. Percent of newborn babies weigh between 6.7 and 9.5 pounds

$P(6.7 \leq x \leq 9.5)\\\\ = P(\displaystyle\frac{6.7 - 7.4}{0.7} \leq z \leq \displaystyle\frac{9.5-7.4}{0.7})\\\\ = P(-1 \leq z \leq 3)\\\\= P(z \leq 3) - P(z < -1)\\= 0.9987 -0.1587= 0.84 = 84\%$

84% of newborn babies weigh between 6.7 and 9.5 pounds.

7 0

3 years ago