Question

Find the distance between V(4,4) and X(5,8). Round to the nearest tenth, if necessary.

Answer 1

Answer:

$(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2} = c^{2}$

$V(x_{1}, y_{1}) = V(4, 4)\\X(x_{2}, y_{2}) = V(5, 8)$

$(5-4)^{2} + (8-4)^{2} = c^{2}\\1^{2} + 4^{2} = c^{2}$

$1+16=c^{2}\\17= c^{2}\\c = \sqrt{17}$

Step-by-step explanation:

Start by plotting your points.

If the line is diagonal, then realize you can make a triangle with the line connecting the two points being the hypotenuse.

Use Pythagorean Theroem to solve.