Get into ax²+bx+c=0 form
subsitute u=x⁴
x⁸-3x⁴+2=0
(x⁴)²-3(x⁴)+2=0
u²-3u+2=0
factor
(u-2)(u-1)=0
set to zero
u-2=0
u=2
u-1=0
u=1
wait, u=x⁴
2=x⁴
![\sqrt[4]{2}=x](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B2%7D%3Dx)
1=x⁴
+/-1=x
the subsitution is u=x⁴
and the possible values for x are -1,
, and 1
A) (f∘g)(-1) = f(g(-1)) = f(1) = -1
b) (g∘f)(1) = g(f(1)) = g(-1) = 1
c) (f∘f)(1) = f(f(1)) = f(-1) = -5
Answer:
A) 0 (no solutions)
Step-by-step explanation:
Solve the equation:
3x - 10(x+2) = 13 - 7x
3x - 10x -20 = 13 - 7x
-7x - 20 = 13 - 7x
-20 = 13
Since both sides are clearly not equal to each other, no solution can satisfy both sides to be equal to each other. So A is correct.
As given by the question
There are given that the point of two-line
Now,
From the condition of a parallel and perpendicular line
If the slopes are equal then the lines are parallel
If the slopes are negative reciprocal then the lines are perpendicular
If the slopes are neither of the above are true then lines are neither
Then,
First, find the slope of both of line
So,
For first-line, from the formula of slope
Now,
For second-line,
The given result of the slope is negative reciprocal because
Hence, the slope of line1 is -1/2, and slope of line2 is 2 and the lines are perpendicular.
I did this last semester and I would remember it but unfortunately this was the only section I didn't study for the final bc we did one day on it. I'm sorry. Good luck.
