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crimeas [40]
2 years ago
10

Steph Curry makes 9 out of 10 free throws. If he shoots 200 free throws how many can he expect to make

Mathematics
1 answer:
MissTica2 years ago
8 0
200 divided by 10 is 20 so You have to X both by 20 so 9 X 20 is 180 and 10 X 20 is 200 I think
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Two of the statements are true; one is a lie.
Temka [501]

Answer:

Statement 3

Step-by-step explanation:

∠GAF ≅ ∠TAE

Since, there is no relation between these angles,

Therefore, statement is False.

∠TAE and ∠FAH are complementary.

If the sum of the two angles is 90°, pair of angles is said to be complimentary angles.

Therefore, this statement is False.

∠TAF is obtuse.

Measure of obtuse angle is more than 90°

From the given picture, measure of ∠TAF = m∠TAH + m∠HAF

                                                                      = 90° + 50°

                                                                      = 140°

Here, m∠TAF > 90°

Therefore, ∠TAF is an obtuse angle.

Statement (3) is the correct statement.

8 0
3 years ago
John, Sally, and Natalie would all like to save some money. John decides that it
brilliants [131]

Answer:

Part 1) John’s situation is modeled by a linear equation (see the explanation)

Part 2)  y=100x+300

Part 3) \$12,300

Part 4) \$2,700

Part 5) Is a exponential growth function

Part 6) A=6,000(1.07)^{t}

Part 7) \$11,802.91

Part 8)  \$6,869.40

Part 9) Is a exponential growth function

Part 10) A=5,000(e)^{0.10t}    or  A=5,000(1.1052)^{t}

Part 11)  \$13,591.41

Part 12) \$6,107.01

Part 13)  Natalie has the most money after 10 years

Part 14)  Sally has the most money after 2 years

Step-by-step explanation:

Part 1) What type of equation models John’s situation?

Let

y ----> the total money saved in a jar

x ---> the time in months

The linear equation in slope intercept form

y=mx+b

The slope is equal to

m=\$100\ per\ month

The y-intercept or initial value is

b=\$300

so

y=100x+300

therefore

John’s situation is modeled by a linear equation

Part 2) Write the model equation for John’s situation

see part 1)

Part 3) How much money will John have after 10 years?

Remember that

1 year is equal to 12 months

so

10\ years=10(12)=120 months

For x=120 months

substitute in the linear equation

y=100(120)+300=\$12,300

Part 4) How much money will John have after 2 years?

Remember that

1 year is equal to 12 months

so

2\  years=2(12)=24\ months

For x=24 months

substitute in the linear equation

y=100(24)+300=\$2,700

Part 5) What type of exponential model is Sally’s situation?

we know that    

The compound interest formula is equal to  

A=P(1+\frac{r}{n})^{nt} 

where  

A is the Final Investment Value  

P is the Principal amount of money to be invested  

r is the rate of interest  in decimal

t is Number of Time Periods  

n is the number of times interest is compounded per year

in this problem we have  

P=\$6,000\\ r=7\%=0.07\\n=1

substitute in the formula above

A=6,000(1+\frac{0.07}{1})^{1*t}\\  A=6,000(1.07)^{t}

therefore

Is a exponential growth function

Part 6) Write the model equation for Sally’s situation

see the Part 5)

Part 7) How much money will Sally have after 10 years?

For t=10 years

substitute  the value of t in the exponential growth function

A=6,000(1.07)^{10}=\$11,802.91 

Part 8) How much money will Sally have after 2 years?

For t=2 years

substitute  the value of t in the exponential growth function

A=6,000(1.07)^{2}=\$6,869.40

Part 9) What type of exponential model is Natalie’s situation?

we know that

The formula to calculate continuously compounded interest is equal to

A=P(e)^{rt} 

where  

A is the Final Investment Value  

P is the Principal amount of money to be invested  

r is the rate of interest in decimal  

t is Number of Time Periods  

e is the mathematical constant number

we have  

P=\$5,000\\r=10\%=0.10

substitute in the formula above

A=5,000(e)^{0.10t}

Applying property of exponents

A=5,000(1.1052)^{t}

 therefore

Is a exponential growth function

Part 10) Write the model equation for Natalie’s situation

A=5,000(e)^{0.10t}    or  A=5,000(1.1052)^{t}

see Part 9)

Part 11) How much money will Natalie have after 10 years?

For t=10 years

substitute

A=5,000(e)^{0.10*10}=\$13,591.41

Part 12) How much money will Natalie have after 2 years?

For t=2 years

substitute

A=5,000(e)^{0.10*2}=\$6,107.01

Part 13) Who will have the most money after 10 years?

Compare the final investment after 10 years of John, Sally, and Natalie

Natalie has the most money after 10 years

Part 14) Who will have the most money after 2 years?

Compare the final investment after 2 years of John, Sally, and Natalie

Sally has the most money after 2 years

3 0
4 years ago
Help please...
stealth61 [152]

Answer:

1) 80%  2)25%

Step-by-step explanation:

1)80% of $2.50 = $4.50

2)25% of $9 = $2.25

  9 - 2.25 = $6.75

7 0
3 years ago
Pg 436 Questions 10-13
Rzqust [24]
10. P- 30 ft , A- 8064
11. P- 18.8 ft, A- 44.8
I know it's only 2 questions but that's all I know sorry :( I hope that I at least helped a little though!
3 0
3 years ago
Solve for the two possible values of X:
lbvjy [14]
X1 = 1.71429
X2 = 3.4
7 0
3 years ago
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