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Marat540 [252]
2 years ago
13

Lila forgot the security code for her apartment building. The code is two different digits followed by a capital letter. How man

y different possible codes are there?
A. 2,106
B. 2,340
C. 2,600

Mathematics
2 answers:
Yanka [14]2 years ago
5 0

Answer:B. 2,340

Step-by-step explanation:

The number of digits = 10  [0,1,2,3,4,5,6,7,8,9]

The number of alphabets = 26

Now we are given that the code is two different digits followed by a capital letter.

Therefore, the number of different possible codes there are  :-

=\ ^{10}P_2\times26=10\times9\times26=2340

Hence, there are 2340 different possible codes.

Nataly [62]2 years ago
4 0
<span>10*9*26=2,340
B.2,340

</span>

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We want to see how we can model the difference: -8 - 3 + 3

The correct option is D:

"add 3 positive counters and 3 negative counters"

We know that Marcus starts with 8 negative counters, corresponding to the first term in our difference.

Now, let's study the math of our expression.

-8 - 3 + 3

Remember that we can perform the operation in any order we want, so we can write this as:

-8 + (-3 + 3)

Notice that the thing inside the parentheses is equal to zero, so we have:

- 8 + (-3 + 3) = -8

So to not change the value, we add 3 and we subtract 3.

Now if we have 8 negative counters, and we want to add 3 positive counters and not change the value, then we also need to add 3 negative counters to "cancel" the 3 positive counters we added.

Then the correct option is D.

To learn more about Marcus refer to,

brainly.com/question/23140234

#SPJ1

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