Answer:B. 2,340
Step-by-step explanation:
The number of digits = 10 [0,1,2,3,4,5,6,7,8,9]
The number of alphabets = 26
Now we are given that the code is two different digits followed by a capital letter.
Therefore, the number of different possible codes there are :-
Hence, there are 2340 different possible codes.
This time round, use SOH method (Sin angle = Opposite/Hypotenuse)
given Opposite = 7
Hypotenuse = 10