Answer:B. 2,340
Step-by-step explanation:
The number of digits = 10 [0,1,2,3,4,5,6,7,8,9]
The number of alphabets = 26
Now we are given that the code is two different digits followed by a capital letter.
Therefore, the number of different possible codes there are :-
Hence, there are 2340 different possible codes.
Answer:
We expand a number to show the value of each digit.
29085:
20,000 + 9,000 + 000 + 80 + 5 = 29085
<em>Hope this helps!!</em>
The graph is skewed to the right.
Part I
Part II
Part III
Part IV
y = 3x - 11
y=mx+b
1=3(4)+b
1=12+b
b=-11
.1 Simplify: 5n(2n3+n2+8)+n(4-n).
Solution:
5n(2n3+n2+8)+n(4-n).
= 5n × 2n3 + 5n × n2 + 5n × 8 + n × 4 - n × n.
= 10n4 + 5n3 + 40n + 4n – n2.
= 10n4 + 5n3 + 44n – n2.
= 10n4 + 5n3 – n2 + 44n.
Answer: 10n4 + 5n3 – n2 + 44n