4s+7a=861
s+a=168
This can be solved using either elimination or substitution. I am going to use substitution.
Solve s+a=168 for s
s=168-a
Replace 168-a for s in 4s+7a=861
4(168-a)+7a=861
672-4a+7a=861
Solve for a
672+3a=861
3a=189
a=63
Substitute 63 for a in s=168-a
s=168-63=105
So, s=105 student tickets and a=63 adult tickets
X= # students who got lower grades
2x+3= # students with grade A
STEP 1:
Add the two sets above equal to 24.
x + (2x + 3)= 24
combine like terms
3x + 3= 24
subtract 3 from both sides
3x= 21
divide both sides by 3
x= 7 (# students lower than A)
STEP 2:
substitute x value from step 1 to find # grade A students
=2x + 3
=2(7) + 3
=14 + 3
=17 (# grade A students)
CHECK:
x + (2x + 3)= 24
7 + 2(7) + 3= 24
7 + 14 + 3= 24
24= 24
ANSWER: There were 17 students with grade A.
Hope this helps! :)
Answer:
-8/5 = -1.6 (the smallest number here)
-5/8 = -0.625
your answer is A :)
Answer:
Total = 36%
Step-by-step explanation:
Given
Company A = 0.15
Company B = 21%
Required
Determine the total revenue
Total is calculated as thus:
Total = Company A + Company B
Total = 0.15 + 21%
Represent 0.15 as %
Total = 0.15*100% + 21%
Total = 15% + 21%
Total = 36%
<span>A is the correct answer for this</span>
