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Sophie [7]
3 years ago
5

Find the sum of number n and two previous numbers

Mathematics
1 answer:
krek1111 [17]3 years ago
3 0

Two previos numbers of <em>n</em><em> </em> are <em>(</em><em> </em><em>n</em><em> </em><em>-</em><em> </em><em>1</em><em> </em><em>)</em><em> </em> and <em>(</em><em> </em><em>n</em><em> </em><em>-</em><em> </em><em>2</em><em> </em><em>)</em><em> </em><em> </em>Thus :

( n - 2) + ( n - 1 ) + n = 3n - 3

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Alex buys a top of the line computer. He did not realize that the computer would lose value so fast. If his computer cost $1800.
Natali [406]

This can be solve by using the formula

D = P( 1 – i)^n

Where d is the depreciation value after n years

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i is the depreciation rate

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D = 1/3 ( 1800)

D = 600

So

600 = 1800 ( 1- 0.45)^n

Solve for n

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3 years ago
Huw has a maths test. the second question is:
xeze [42]

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The number of days that the food can last 30 guests is 4 days.

<h3>How long will Seaview Hotel's food feed 30 guests?</h3>

More guests would eat the food faster which means that it would be finished in less days than the 6 days used by 20 guests.

To find the days the food would last 30 guests, use the inverse proportion formula:
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Full question is:

The only food provided for guests at Seaview Hotel is breakfast. The hotel has enough food to make breakfast for 20 guests for 6 days. How long would the food last 30 guests? You may assume each guest eats the same amount of food for breakfast.

Without working out the correct answer, explain why Huw’s answer of 9 days is incorrect.

Find out more on inverse proportion at brainly.com/question/1266676.

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5 0
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Murrr4er [49]

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timofeeve [1]
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Read 2 more answers
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