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Ket [755]
3 years ago
7

you are working as a Caterer and need 20 gallons of lemonade For an upcoming event. The bottles of lemonade you are purchasing a

re in liters
Mathematics
2 answers:
mariarad [96]3 years ago
7 0
YOUR ANSWER IS 320 WELCOME
kifflom [539]3 years ago
3 0
20 imperial gallons = 90.9218 litres 
so i'd say you'd need to buy 91 bottles or...

20 US Liquid gallons = 75.7082 litres 
so you'd have to buy 76 bottles.
Hope this answers your question! It depends what gallon you're working from.
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The operation manager at a tire manufacturing company believes that the mean mileage of a tire is 48,564 miles, with a standard
DerKrebs [107]

Answer:

0.0091 = 0.91% probability that the sample mean would be less than 48,101 miles in a sample of 281 tires if the manager is correct

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, the sample means with size n of at least 30 can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 48564, \sigma = 3293, n = 281, s = \frac{3293}{\sqrt{281}} = 196.44

What is the probability that the sample mean would be less than 48,101 miles in a sample of 281 tires if the manager is correct?

This is the pvalue of Z when X = 48101. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{48101 - 48564}{196.44}

Z = -2.36

Z = -2.36 has a pvalue of 0.0091

0.0091 = 0.91% probability that the sample mean would be less than 48,101 miles in a sample of 281 tires if the manager is correct

6 0
3 years ago
I need help please and thank you!!!!
Naddika [18.5K]

Answer:

Bottom left graph.

Step-by-step explanation:

I answered this by finding the y-int.

8(0) - 3y = 18

-3y = 18

y = -6

And it has a positive relationship so the line slants from bottom left to top right.

4 0
3 years ago
0.27 (repeating) into a fraction. Simplify if needed.
WARRIOR [948]
Dont ask me why...I cant really explain it...but if u have 1 repeating decimal, u put it over 9. If u have 2 repeating decimals, u put it over 99....3 repeating decimals, put it over 999.

Examples :
0.7 (repeating) = 7/9
0.27 (repeating) = 27/99 when simplified = 3/11 <===
0.444 (repeating = 444/999 
8 0
3 years ago
Read 2 more answers
A recent trend in advertising is viral marketing. The goal is to convince viewers to share an amusing advertisement by e-mail or
77julia77 [94]
I'm not sure what you are looking for but I'll answer this question based on what I think is needed.

Given:
Day 1: 130 
Day 2: 130 x 4 = 520
Day 3: 520 x 4 = 2,080

The exponential equation of this problem is:
V(n) = 130(4)^n

Where n is the number of days since the video was first shown.

Let us assume that 10 days have past. Total view would be:

V(n) = 130(4)^n

V(10) = 130(4)^10
V(10) = 130(1,048,576)
V(10) = 136,314,880

After 10 days, there are more than 136 Million views of the viral video.



5 0
3 years ago
The length of a rectangle is four times its width. If the area of the rectangle is 100 ft², find its perimeter
olga2289 [7]

Answer:

suck dickpula

asda

<h2>Step-by-step explanation:</h2>

3 0
3 years ago
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