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Ket [755]
3 years ago
7

you are working as a Caterer and need 20 gallons of lemonade For an upcoming event. The bottles of lemonade you are purchasing a

re in liters
Mathematics
2 answers:
mariarad [96]3 years ago
7 0
YOUR ANSWER IS 320 WELCOME
kifflom [539]3 years ago
3 0
20 imperial gallons = 90.9218 litres 
so i'd say you'd need to buy 91 bottles or...

20 US Liquid gallons = 75.7082 litres 
so you'd have to buy 76 bottles.
Hope this answers your question! It depends what gallon you're working from.
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2y - 4x = 4 Rewrite:
USPshnik [31]

Answer:

y - 2x = 2

Step-by-step explanation:

2y - 4x = 4

2(y - 2x) = 4  | : 2

y - 2x = 2

6 0
3 years ago
Read 2 more answers
Which of the following is the sum of the slopes of the line 3x+y=1 and a line perpendicular to this line? A 0 B 13 C −83 D −6
laiz [17]

Answer:

-8/3

Step-by-step explanation:

First find the slope of the line

3x+y = 1

Solve for y

y = -3x+1

This is in slope intercept form

y = mx+b where m is the slope

The slope is -3

The slopes of perpendicular lines multiply to -1

m* -3 = -1

m = 1/3

The line perpendicular has a slope of 1 / (3) = 1/3

The sum is -3 + 1/3

-9/2 + 1/3 = -8/3

3 0
3 years ago
A beacon is flashing on top of a 50 foot tower. A 6 foot tall man walks constantly away from the tower at 5 feet/sec. At the ins
Viefleur [7K]

Answer:\frac{253}{44}

Step-by-step explanation:

ignore the "at the instant the man is 30 feet away" part, set it as X and the man's shadow as Y.

Similar triangles so we can do \frac{50}{x+y}  = \frac{6}{y}.

Solve for it we get 44y = 6x

Differentiate relative to time t, we get 44y' = 6x'.

change in x (x') is equal to 5. And we get the answer y' = \frac{33}{44}.

the \frac{33}{44} ft/sec is the rate of which the length of the shadow is changing. add 5 to it for the rate of the tip of his shadow moving away from the tower.

7 0
2 years ago
What is the domain of the function shown in thr table
Reil [10]
Option A ( 2 , 4 , 6 , 8) because domain are x values
4 0
2 years ago
Assuming the pattern continues, what are the next two terms in this
pshichka [43]
D. 53, 107
The pattern is multiplying the previous number by two and then adding one to it.
4 0
3 years ago
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