Viết cấu hình electron nguyên tử các nguyên tố có số electron từ 1 đến 10

Chemistry

1 answer:

Dmitry [639]3 years ago

5 0

Explanation:

Element Atomic number Electronic configuration Hydrogen 1 1 Helium 2 2 Lithium 3 2,1 Beryllium 4 2,2 Boron 5 2,3 Carbon 6 2,4 Nitrogen 7 2,5 Oxygen 8 2,6 Fluorine 9 2,7 Neon 10 2,8

The elements of these groups are called representative elements.

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Compare metals and non-metals in terms of their

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Answer:

metals and non metals are compared are above

Explanation:

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If an acid or alkali is diluted by a factor of 10, what effect will this have on its pH?

Alisiya [41]

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Given these reactions, where X represents a generic metal or metalloid 1 ) H 2 ( g ) + 1 2 O 2 ( g ) ⟶ H 2 O ( g ) Δ H 1 = − 241

anygoal [31]

Answer : The enthalpy of the given reaction will be, -1048.6 kJ

Explanation :

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

The main reaction is:

$XCl_4(s)+2H_2O(l)\rightarrow XO_2(s)+4HCl(g)$ $\Delta H=?$

The intermediate balanced chemical reactions are:

(1) $H_2(g)+\frac{1}{2}O_2(g)\rightarrow H_2O(g)$ $\Delta H_1=-241.8kJ$

(2) $X(s)+2Cl_2(g)\rightarrow XCl_4(s)$ $\Delta H_2=+461.9kJ$

(3) $\frac{1}{2}H_2(g)+\frac{1}{2}Cl_2(g)\rightarrow HCl(g)$ $\Delta H_3=-92.3kJ$

(4) $X(s)+O_2(g)\rightarrow XO_2(s)$ $\Delta H_4=-789.1kJ$

(5) $H_2O(g)\rightarrow H_2O(l)$ $\Delta H_5=-44.0kJ$

Now reversing reaction 2, multiplying reaction 3 by 4, reversing reaction 1 and multiplying by 2, reversing reaction 5 and multiplying by 2 and then adding all the equations, we get :

(1) $2H_2O(g)\rightarrow 2H_2(g)+O_2(g)$ $\Delta H_1=2\times 241.8kJ=483.6kJ$