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Luden [163]
3 years ago
12

Solve for k. 11 k 11 8 4 k= ?

Mathematics
2 answers:
melomori [17]3 years ago
7 0

Answer:

Step-by-step explanation:

11+11=22x8=176-4=172

k=172

olga nikolaevna [1]3 years ago
4 0

Answer:

lol i have same

Step-by-step explanation:

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When a positive number is multiplied by the sum of twice the number and half the number, the result is the original number. What
ValentinkaMS [17]
The number will be itself when multiplied by 1.

The sum of twice and half the original number is 1, so the number is
  2n +0.5n = 1
  2.5n = 1
  n = 1/2.5 = 0.4

The original number is 2/5.
5 0
3 years ago
Identify the constants from this expression.<br> 5x - 7x + 5 - 12 + 4x - 3
skelet666 [1.2K]

Answer:

5, -12, -3

Step-by-step explanation:

A constant is a number by itself. Here, you can see that 5X is paired with a letter, that means that 5X is not a constant. So you could say that any whole number is a constant number and in this problem, 5, -12 and -3 are all the constant numbers in this expression.

5 0
3 years ago
(x + y + z = 3<br> -y = x<br> 2z + 3y = 0<br> What does x and y equal?
NeTakaya

Answer:

x=2 and y=-2

Step-by-step explanation:

7 0
3 years ago
Rolando is 13. In five years, his age will be 3/2 the age of his sister Marisa. How old will Marisa be in three years?
nalin [4]
13+5 = 1.5m
18 = 1.5m
m=12

her age in three years = 12+3= 15 years old
4 0
3 years ago
A ball is thrown vertically upward from the top of a building 160 feet tall with an initial velocity of 48 feet per second. The
alina1380 [7]

Answer:

# after 5 seconds, the ball strikes the ground

# The ball reaches maximum height at t = 1.5 seconds

# The max height is 196 feet

Step-by-step explanation:

The equation is:

d(t)=-16t^2+48t+160

t is the time

d(t) is the distance traveled

Initial height is 160 feet and initial velocity is 48 ft/sec

If we want to find the time it takes the ball to hit the ground, we let d(t) equal to 0 and find t. Shown below:

-16t^2+48t+160=0\\t^2-3t-10=0\\(t-5)(t+2)=0\\t=5,-2

We disregard t = -2 since time can't be negative. We take t = 5

Thus, after 5 seconds, the ball strikes the ground.

The equation is a quadratic of the form: ax^2+bx+c

Matching equations, we can say:

a = -16

b = 48

c = 160

The time when ball reaches max height is given as:

t=-\frac{b}{2a}

Substituting, we find:

t=-\frac{b}{2a}\\t=-\frac{48}{2(-16)}\\t=1.5

The ball reaches maximum height at t = 1.5 seconds

The max height can be found by putting t = 1.5 into the original equation. Shown below:

d(t)=-16t^2+48t+160\\d(1.5)=-16(1.5)^2+48(1.5)+160\\=196

The max height is 196 feet

8 0
3 years ago
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