1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
kenny6666 [7]
3 years ago
8

Select the correct answer. Consider the function represented by this graph. y 6- 4 2- X 2 2 -2- -6 B which word or phrase descri

bes the value of the function over the interval[-6, 0); O A increasing B. constant C. increasing to decreasing D. decreasing​
Mathematics
1 answer:
Gekata [30.6K]3 years ago
8 0

Answer:

bxcdxdbdbdbdxxbdxdbbxd

Step-by-step explanation:

You might be interested in
What is the variable for 2x - 6 = 10
vampirchik [111]

Answer:

Step-by-step explanation:

2x - 6 = 10

2x = 16

x = 8

6 0
4 years ago
The formula for finding the
Advocard [28]

Answer:

25%

Step-by-step explanation:

100-80=20

20/80Ⅹ100=25%

8 0
2 years ago
System by Substitution <br><br> -3x-3y= -12<br> Y=0
alex41 [277]
Substitute the 0 in for y:
-3x - 3(0) = -12
-3x - 0 = -12
-3x = -12

Divide by -3:
-12/-3= 4

Answer:
x = 4

7 0
3 years ago
Find the gradient of the line Joining the points p(-2,6) and Q(3,-2)​
Rudiy27

Answer:

-  \frac{8}{5}

Step-by-step explanation:

\boxed{gradient =  \frac{y1 - y2}{x1 - x2} }

(x₁, y₁) is the 1st coordinate while (x₂, y₂) is the 2nd coordinate.

Gradient of the line

=  \frac{6 - ( - 2)}{ - 2 - 3}

=  \frac{6 + 2}{ - 5}

=   - \frac{8}{5}

7 0
3 years ago
John, Johan, and Jonathan collect postage stamps. Johan and Jonathan have the same number of stamps. Two times Johan’s collectio
kati45 [8]
Let d = number of stamps from John (4 letters, d is 4th letter, etc) 
<span>Let e = number of stamps from Johan </span>
<span>Let h = number of stamps from Jonathan </span>

<span>Johan and Jonathan have the same number of stamps, so: </span>

<span>e = h </span>

<span>2 times Johan's collection is 11 less than 5 times John's collection, so: </span>

<span>2e = 5d - 11 </span>

<span>3 times Jonathan's collection is 3 less than 7 times John's collection,so: </span>

<span>3h = 7d - 3 </span>

<span>Now we have three equations and three unknowns. You're asked for the number of stamps in John's collection, so you want the value to variable "d". </span>

<span>Since e = h, we can substitute "h" for "e" in the second equation. </span>

<span>2h = 5d - 11 </span>
<span>3h = 7d - 3 </span>

<span>now we have two equations and two unknowns. I'll use elimination, starting with multiplying the first equation by -3 and the second one by 2. </span>

<span>-6h = -15d + 33 </span>
<span>6h = 14d - 6 </span>

<span>now add both together and you have an equation with one unknown remaining: </span>

<span>0 = -d + 27 </span>
<span>d = 27 </span>

<span>So your answer is 27 stamps. If you want to know how many stamps the others have, you can work back and solve for e and h.</span>
7 0
4 years ago
Read 2 more answers
Other questions:
  • Sean places 28 tomato plants in rows. All rows contain the same number of plants. There are between 5 and 12 plants in each row
    15·1 answer
  • Given that the radius of circle A is 4 cm, and the diameter of circle B is 6 cm, what can be concluded about the two circles. So
    10·1 answer
  • 2319 to nearest hundred
    10·1 answer
  • What number goes in the box to make the equation true? Blank = 5/16 x 8/15
    8·1 answer
  • A store owner paid $15 dollars for ia
    11·2 answers
  • Which is greater 2 1/3 or 2.3
    5·2 answers
  • What inequality symbol does "at least" correspond to?
    13·1 answer
  • 0.75x — 13 = 2<br> What's the value of x
    8·1 answer
  • Boris chosen three different numbers. The sum of the numbers is 36. One of the numbers is a cube number the other two numbers ar
    15·1 answer
  • An angle measures 38° less than the measure of its complementary angle. What is the measure of each angle?
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!