2 years ago

If f(x) = 3x - 1 and g(x) = x + 2, find (f+g)(x)

1 answer:

Ivan2 years ago

5 0

Answer:

(f - g)(x) = f(x) - g(g) = (3x + 1) - (x2 - 6) = -x^2 + 3x + 7

Step-by-step explanation:

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irga5000 [103]

Answer:

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Step-by-step explanation:

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4 years ago

Nat2105 [25]

Answer:

The answer to your question is: $\sqrt[4]{2^{3} } + 1$

Step-by-step explanation:

$\frac{1}{\sqrt[4]{2- 1}} x \frac{\sqrt[4]{2^{3}}+ 1 }{\sqrt[4]{2^{3}} + 1} = [tex]\frac{\sqrt[4]{2^{3}}+ 1 }{2 - 1}$

= $\sqrt[4]{2^{3} } + 1$

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4 years ago

Inessa [10]

5= (6+4)x
5= 10x

5= 10x then divide by 10 to get the variable by itself
__ ___
10 10
.5 = x you can use .5 or 1/2

hope this helps!
:)

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3 years ago

Tpy6a [65]

Answer:

what?

Step-by-step explanation:

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3 years ago

maxonik [38]

I am not sure but I think I know ok

4 0

3 years ago

If f(x) = 3x - 1 and g(x) = x + 2, find (f+g)(x)​