By the law of cosines, the angle
![C](https://tex.z-dn.net/?f=C)
satisfies
![8.77^2=2^2+9^2-2\times2\times9\times\cos C](https://tex.z-dn.net/?f=8.77%5E2%3D2%5E2%2B9%5E2-2%5Ctimes2%5Ctimes9%5Ctimes%5Ccos%20C)
which reduces to
![\cos C=0.2246\implies C=\arccos(0.2246)\approx1.34422\text{ rad}](https://tex.z-dn.net/?f=%5Ccos%20C%3D0.2246%5Cimplies%20C%3D%5Carccos%280.2246%29%5Capprox1.34422%5Ctext%7B%20rad%7D)
which converts to approximately 77 degrees (this can be done my multiplying by 180 and dividing by pi).
9514 1404 393
Answer:
r = 14.5
Step-by-step explanation:
AD is the perpendicular bisector of chord EC, so is the diameter of the circle. The radius is half the diameter.
r = AD/2 = (AB +BD)/2 = (25 +4)/2 = 29/2
r = 14.5
__
Segments BE and BC are 10 = √(25·4)
Answer:
y = 50 + 35x we dont know how many hours they worked
Step-by-step explanation:
Remember that the area of a square is just one of its sides squared.
![A=s^2](https://tex.z-dn.net/?f=A%3Ds%5E2)
where
![A](https://tex.z-dn.net/?f=A)
is the area of the square
![s](https://tex.z-dn.net/?f=s)
is one of the sides of the square
Unit square is a square whose sides have length 1, so lets use our formula to find the volume of one unit square:
![A=s^2](https://tex.z-dn.net/?f=A%3Ds%5E2)
![A=1^2](https://tex.z-dn.net/?f=A%3D1%5E2)
![A=1](https://tex.z-dn.net/?f=A%3D1)
We now know that each one of the squares has area 1 unit squared. Since there are 28 unit square in our figure, we are going to multiply the area of a unit square by 28 to find the area of our figure:
Area of the figure=
![28(1)=28](https://tex.z-dn.net/?f=28%281%29%3D28)
units squared
We can conclude that the area of the figure is 28 units squared.
Answer:
y = -2x + 7 and y = x - 2
Step-by-step explanation:
2x + y = 7
y = -2x +7
x - y = 2
-y = -x +2
y = x - 2