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3 years ago

What is the reciprocal of 2⅜

Mathematics

1 answer:

Fittoniya [83]3 years ago

5 0

Answer:

8/19

Step-by-step explanation:

Use this rule: a b/c=ac+b/c

2x8+3/8

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The slope of the line containing the points (-2,3) and (-3,1) is

Irina18 [472]

To calculate the slope containing two points, we can use that formula:

$\mathsf{m=\dfrac{y_2-y_1}{x_2-x_1}}$

"m" represents the slope and coordinates are expressed as follows: (x, y)

Let's go to the calculations.

$\mathsf{m=\dfrac{y_2-y_1}{x_2-x_1}}\\\\\\ \mathsf{m=\dfrac{1-3}{-3-(-2)}}\\\\\\ \mathsf{m=\dfrac{-2}{-3+2}}\\\\\\ \mathsf{m=\dfrac{-2}{-1}}\\\\\\ \mathsf{m=\dfrac{2}{1}}\\\\\\ \underline{\mathsf{m=2}}$

The answer is 2 uc.

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2 years ago

Sam had monkeys and lions in his zoo, He counted legs one day to discover that he could see 76 feet on the ground. He knew that

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3 years ago

$(x) = -22 +22. - 114

galina1969 [7]

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Step-by-step explanation:

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3 years ago

Read 2 more answers

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3 years ago

Evaluate cube root of 5 multiplied by square root of 5 over cube root of 5 to the power of 5.

Andre45 [30]

Answer:

Option d) 5 to the power of negative 5 over 6 is correct.

$\dfrac{\sqrt[3]{\bf 5} \times \sqrt{\bf 5}}{\sqrt[3]{\bf 5^{\bf 5}}}= 5^{\frac{\bf -5}{\bf 6}}$

Above equation can be written as 5 to the power of negative 5 over 6.

ie, $5^\frac{\bf -5}{\bf 6}$

Step-by-step explanation:

Given that cube root of 5 multiplied by square root of 5 over cube root of 5 to the power of 5.

It can be written as below

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{1}{3}} \times 5^{\frac{1}{2}}}{5^{\frac{5}{3}}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{1}{3}+\frac{1}{2}}}{5^{\frac{5}{3}}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{2+3}{6}}}{5^{\frac{5}{3}}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= 5^{\frac{5}{6}} \times 5^{\frac{-5}{3}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= 5^{\frac{5-10}{6}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{5^5}= 5^{\frac{-5}{6}}$

Above equation can be written as 5 to the power of negative 5 over 6.

7 0

3 years ago

What is the reciprocal of 2⅜​

What is the reciprocal of 2⅜