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Temka [501]
2 years ago
9

How many whole numbers are there between 32 and 96?

Mathematics
1 answer:
Inessa05 [86]2 years ago
6 0

Answer:

there are 20 while numbers between 32 and 96

Step-by-step explanation:

hope it helps and give me a brainliest

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The Baltimore Zoo feeds their elephants a combination of fruit and grass. The zookeeper would like to create a model to represen
Anika [276]

A function can be represented on a table and on a graph.

The models of the linear relationship between f(x) and x are:

\mathbf{A.\ f(x) = 30x + 22}\\\mathbf{C.\ The\ table}\\\mathbf{F.\ The\ graph}

The given parameters are:

\mathbf{Start = 22}

\mathbf{Additional = 30}

So, the function that models the linear relationship is:

\mathbf{f(x) = Start + Additional \times x}

Substitute known values

\mathbf{f(x) = 22 + 30 \times x}

Evaluate all products

\mathbf{f(x) = 22 + 30x}

Rewrite as:

\mathbf{f(x) = 30x + 22}

By comparing the above function to the list of options, we have the true options to be:

\mathbf{A.\ f(x) = 30x + 22}\\\mathbf{C.\ The\ table}\\\mathbf{F.\ The\ graph}

Read more about linear functions at:

brainly.com/question/20286983

4 0
3 years ago
The distribution of income tax refunds follow an approximate normal distribution with a mean of $7010 and a standard deviation o
Andrej [43]

Answer:

A refund must be above $7,139 before it is audited.

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed random variable:

Approximately 68% of the measures are within 1 standard deviation of the mean.

Approximately 95% of the measures are within 2 standard deviations of the mean.

Approximately 99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Mean = 7010, standard deviation = 43.

Approximately 99.7% of the measures are within 3 standard deviations of the mean.

The empirical rule is symmetric, which means that the lowest (100-99.7)/2 = 0.15% is at least 3 standard deviations below the mean, and the upper 0.15% is at least 3 standard deviations above the mean.

Use the Empirical Rule to determine approximately above what dollar value must a refund be before it is audited.

3 standard deviations above the mean, so:

7010 + 3*43 = 7139.

A refund must be above $7,139 before it is audited.

5 0
3 years ago
This spring it rained a total of 11.5 inches. This was 3 inches less than last spring. Write and solve an equation to find the a
inna [77]

Answer:

11.5-3= 8.5

Step-by-step explanation:

5 0
3 years ago
The diameter of a particle of contamination (in micrometers) is modeled with the probability density function f(x)= 2/x^3 for x
RoseWind [281]

Answer:

a) 0.96

b) 0.016

c) 0.018

d) 0.982

e) x = 2

Step-by-step explanation:

We are given with the Probability density function f(x)= 2/x^3 where x > 1.

<em>Firstly we will calculate the general probability that of P(a < X < b) </em>

       P(a < X < b) =  \int_{a}^{b} \frac{2}{x^{3}} dx = 2\int_{a}^{b} x^{-3} dx

                            = 2[ \frac{x^{-3+1} }{-3+1}]^{b}_a   dx    { Because \int_{a}^{b} x^{n} dx = [ \frac{x^{n+1} }{n+1}]^{b}_a }

                            = 2[ \frac{x^{-2} }{-2}]^{b}_a = \frac{2}{-2} [ x^{-2} ]^{b}_a

                            = -1 [ b^{-2} - a^{-2}  ] = \frac{1}{a^{2} } - \frac{1}{b^{2} }

a) Now P(X < 5) = P(1 < X < 5)  {because x > 1 }

     Comparing with general probability we get,

     P(1 < X < 5) = \frac{1}{1^{2} } - \frac{1}{5^{2} } = 1 - \frac{1}{25} = 0.96 .

b) P(X > 8) = P(8 < X < ∞) = 1/8^{2} - 1/∞ = 1/64 - 0 = 0.016

c) P(6 < X < 10) = \frac{1}{6^{2} } - \frac{1}{10^{2} } = \frac{1}{36} - \frac{1}{100 } = 0.018 .

d) P(x < 6 or X > 10) = P(1 < X < 6) + P(10 < X < ∞)

                                = (\frac{1}{1^{2} } - \frac{1}{6^{2} }) + (1/10^{2} - 1/∞) = 1 - 1/36 + 1/100 + 0 = 0.982

e) We have to find x such that P(X < x) = 0.75 ;

               ⇒  P(1 < X < x) = 0.75

               ⇒  \frac{1}{1^{2} } - \frac{1}{x^{2} } = 0.75

               ⇒  \frac{1} {x^{2} } = 1 - 0.75 = 0.25

               ⇒  x^{2} = \frac{1}{0.25}   ⇒ x^{2} = 4 ⇒ x = 2  

Therefore, value of x such that P(X < x) = 0.75 is 2.

8 0
3 years ago
Re-write the following problem using a different form of rational numbers. Then solve using that different form of rational numb
Effectus [21]

Answer:

-6.85

Step-by-step explanation:

8 0
3 years ago
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