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stira [4]
3 years ago
12

If street lights are placed at most 145

Mathematics
1 answer:
Paraphin [41]3 years ago
7 0

Answer:

Step-by-step explanation:

d=4 miles=4×1760 yards=7040 yards=7040×3 ft

number of lights=21120 ft

number of lights=21120/145 +1≈145.7+1=146+1=147 lights

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Perform the indicated operation.<br><br> 11(-2)<br><br> 22<br> 9<br> -9<br> -22
ASHA 777 [7]

Answer:

<u>-22</u>

Step-by-step explanation:

When you multiply a positive and negative number together, it becomes negative.

Multiplication is repetitive addition.

11(-2) = -11 + -11 = -22

3 0
3 years ago
The table shows data gathered by an environmental agency about the decreasing depth of a lake during the first few months of a d
Elanso [62]
(0,346)(2,344.8)
slope = (344.8 - 346) / (2 - 0) = -1.2 / 2 = -0.6

y = mx + b
slope(m) = -0.6
(0,346)...x = 0 and y = 346
now we sub and find b, the y int
346 = -0.6(0) + b
346 = b
so ur equation is : y = -0.6x + 346....with x being the number of weeks

after 4 weeks...
y = -0.6(4) + 346
y = - 2.4 + 346
y = 343.6 <==== after 4 weeks

after 9 weeks..
y = -0.6(9) + 346
y = -5.4 + 346
y = 340.6 <=== after 9 weeks

7 0
3 years ago
Could I get the awnser and explanation of this? Thank you!
astra-53 [7]

Answer:

equation: y = 4x-12

slope: 4

y-intercept: -12

Step-by-step explanation:

3 points across an x-axis is +1 x-axis difference and +4 y-axis away from origin, so you have to subtract 3 by 1 andsubtract y by 4. until x is 0, you get -12 on y-axis

6 0
3 years ago
What is 65 cm expressed in meters?<br> Plz, respond FAST!!!!
Digiron [165]
65 cm= 0.65 m. Hope this helps!

5 0
3 years ago
Read 2 more answers
Starting with x1 = 2, find the third approximation x3 to the root of the equation x3 − 2x − 2 = 0.
andrew11 [14]

Answer:

0.8989

Step-by-step explanation:

Using the Newton's Raphson approximation formula.

Xn+1 = Xn - f(Xn)/f'(Xn)

Given f(x) = x³-2x+2

f'(x) = 3x²-2

If the initial value X1 = 2

X2 = X1 - f(X1)/f'(X1)

X2 = 2 - f(2)/f'(2)

f(2) = 2³-2(2)+2

f(2) = 8-4+2

f(2) = 6

f'(2) = 3(2)²-2

f'(2) = 10

X2 = 2- 6/10

X2 = 14/10

X2 = 1.4

X3 = X2 - f(X2)/f'(X2)

X3 = 1.4 - f(1.4)/f'(1.4)

f(1.4) = 1.4³-2(1.4)+2

f(1.4) = 2.744-2.8+2

f(1.4) = 1.944

f'(1.4) = 3(1.4)²-2

f'(1.4) = 3.880

X3 = 1.4- 1.944/3.880

X3 = 1.4 - 0.5010

X3 = 0.8989

Hence the value of X3 is 0.8989

6 0
3 years ago
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