June 19th 2006 specifically a monday
Answer:
keep going you got it
Step-by-step explanation:
For large sample confidence intervals about the mean you have:
xBar ± z * sx / sqrt(n)
where xBar is the sample mean z is the zscore for having α% of the data in the tails, i.e., P( |Z| > z) = α sx is the sample standard deviation n is the sample size
We need only to concern ourselves with the error term of the CI, In order to find the sample size needed for a confidence interval of a given size.
z * sx / sqrt(n) = width.
so the z-score for the confidence interval of .98 is the value of z such that 0.01 is in each tail of the distribution. z = 2.326348
The equation we need to solve is:
z * sx / sqrt(n) = width
n = (z * sx / width) ^ 2.
n = ( 2.326348 * 6 / 3 ) ^ 2
n = 21.64758
Since n must be integer valued we need to take the ceiling of this solution.
n = 22
Answer:
70cm
Step-by-step explanation:
,
Since, both of the tank posses the same quantity of water then there volume is the same thing
For rectangular base
Volume= (Lenght × breadth × hheight)
If we substitute values
Lenght= 80 cm
Breadth= 70 cm
height= 45 cm
Volume= 80cm × 70cm × 45cm
Volume= 252000cm^3
For square base
Volume= (side)^2 × height
side =60cm.
But volume of square base= volume of
rectangular base
252000cm^3= 60^2 × height
Height= (252000cm^3)/(60^2 )
Height= 70 cm
Hence, the second tank is 70 cm deep
