Answer:
The answers are that a = -5 and b = 1
Step-by-step explanation:
In order to find A and B, we first need to find the equation of the line. We can do this by using two ordered pairs and the slope formula. For the purpose of this activity, I'l use (0, 5) and (-3, 11)
m(slope) = (y2 - y1)/(x2 - x1)
m = (11 - 5)/(-3 - 0)
m = 6/-3
m = -2
Now that we have this we can model this using point-slope form.
y - y1 = m(x - x1)
y - 5 = -2(x - 0)
y - 5 = -2x
y = -2x + 5
Now that we have the modeled equation we can use the ordered pair (a, 15) to solve for a.
y = -2x + 5
15 = -2(a) + 5
10 = -2a
-5 = a
And we can also solve for b using the ordered pair (2, b)
y = -2x + 5
b = -2(2) + 5
b = -4 + 5
b = 1
Answer:
Number of calls expected in next week by manager = 7940
Average Number of calls that call center agent will attend in an hour =7 calls
It is also given that, Call center remain open for 10 hours 5 days a week.
Also, it is given that, full time agents work 40 hours a week but are only on call for 35 hours per week ,Part time agents work 20 hours a week but are only on calls 17 hours per week .
⇒Number of hours worked by full time agents × Number of calls attended in an hour × Number of full time agents + Number of hours worked by Part time agents × Number of calls attended in an hour × Number of Part time agents ≤ 7940
⇒35 × 7×Number of full time agents +17 × 7 ×Number of Part time agents ≤ 7940
Option A
⇒35×15×7+17×7×15
= 3675+1785
= 5460
Option B
⇒35 ×7×20+17×7×7
=4900 +833
= 5733
Option C
⇒35×20×7 +17×20×7
=4900+2380
=7280
Option D
⇒25 × 35×7+17×7×5
=6125 +595
=6720
Option E
⇒28×35×7+17×7×10
=6860+1190
=8050
Option E, ⇒ 28 full time agents and 10 part time agents , is best to meet the scheduling needs is most appropriate, that is nearer to 7940 calls.
