Ask question

Ask question

All categories

faltersainse [42]

2 years ago

11

PLEASE HELPPPP MEEEE!! first gets brainliest

2 answers:

vivado [14]2 years ago

8 0

The answer is d! You do 4.4a-2.9a and get 1.5a and then -7.3-2.9 and get -0.5

jeka942 years ago

4 0

(-2.9a + 6.8) + (4.4a - 7.3)
= -2.9a + 6.8 + 4.4a - 7.3
Combine like terms. All "a" terms can only be added to other "a" terms, and all non variable terms can only be added to other non variable terms.
= 1.5a - 0.5

Final Answer: D. 1.5a - 0.5

You might be interested in

Which value, when placed in the box, would result in a system of equations with infinitely many solutions?

ira [324]

<span>For a system of equations to have infinitely many solutions, the equations have to be lineary dependent, (i.e. one of the equations is a multiple of the other equation). For the given equation to have infinitely many solutions, the second equation have to be a multiple of the first equation. The first equation can be rewritten as y - 2x = -5 The second equation is the first equation multiplied by 2, i.e. 2(y - 2x= -5) = 2y - 4x = -10 Therefore, the correct answer is -10 (option a).</span>

7 0

3 years ago

Read 2 more answers

Please help me i need an answer

azamat

C. 4<=C<=12

Hope that helps

5 0

3 years ago

Rachel jogged along a trail that was 1/4 (fraction) of a mile long. She jogged along the trail 8 times. How many miles did Rache

OverLord2011 [107]

1/4+1/4+1/4+1/4+1/4+1/4+<span>1/4+1/4 = 8 Miles

1/4+1/4 = 1/2 Mile

1/2+1/2 = 1 Mile

1+1 = 2 Miles</span>

5 0

3 years ago

Read 2 more answers

Here's the question.

OleMash [197]

Answer:

The value of T₂₀ - T₁₅ is <u>-20</u>.

Step-by-step explanation:

<u>Given</u> :

>> If for an A.P, d = -4

<u>To</u><u> </u><u>Find</u> :

>> T₂₀ - T₁₅

<u>Using Formula</u> :

General term of an A.P.

$\star{\small{\underline{\boxed{\sf{\red{ T_n = a + (n - 1)d}}}}}}$

>> Tₙ = nᵗʰ term
>> a = first term
>> n = no. of terms
>> d = common difference

<u>Solution</u> :

Firstly finding the A.P of T₂₀ by substituting the values in the formula :

${\dashrightarrow{\pmb{\sf{ T_n = a + (n - 1)d}}}}$

${\dashrightarrow{\sf{ T_{20} = a + (20 - 1) d}}}$

${\dashrightarrow{\sf{ T_{20} = a + (19)d}}}$

${\dashrightarrow{\sf{ T_{20} = a + 19 \times d}}}$

${\dashrightarrow{\sf{ T_{20} = a + 19d}}}$

${\star \: {\underline{\boxed{\sf{\pink{ T_{20} = a + 19d}}}}}}$

Hence, the value of T₂₀ is a + 19d.

$\rule{190}1$

Secondly, finding the A.P of T₁₅ by substituting the values in the formula :

${\dashrightarrow{\pmb{\sf{ T_n = a + (n - 1)d}}}}$

${\dashrightarrow{\sf{ T_{15}= a + (15 - 1) d}}}$

${\dashrightarrow{\sf{ T_{15}= a + (14) d}}}$

${\dashrightarrow{\sf{ T_{15}= a + 14 \times d}}}$

${\dashrightarrow{\sf{ T_{15}= a + 14d}}}$

${\star{\underline{\boxed{\sf \pink{ T_{15}= a + 14d}}}}}$

Hence, the value of T₁₅ is a + 14d

$\rule{190}1$

Now, finding the difference between T₂₀ - T₁₅ :

${\dashrightarrow{\pmb{\sf{T_{20} - T_{15}}}}}$

${\dashrightarrow{\sf{(a + 19d) - (a + 14d)}}}$

${\dashrightarrow{\sf{a + 19d - a - 14d}}}$

${\dashrightarrow{\sf{a - a + 19d - 14d}}}$

${\dashrightarrow{\sf{0+ 19d - 14d}}}$

${\dashrightarrow{\sf{19d - 14d}}}$

${\dashrightarrow{\sf{5 \times - 4}}}$

${\dashrightarrow{\sf{ - 20}}}$

${\star \: \underline{\boxed{\sf{\pink{T_{20} - T_{15} = - 20}}}}}$

Hence, the value of T₂₀ - T₁₅ is -20.

$\underline{\rule{220pt}{3.5pt}}$

3 0

2 years ago

Solve the equation<br><br><br> 12 - 27n2 = 0<br> 9, 3<br> (2/3), (-2/3)<br> (3/2), (-3/2)<br> 2, 3

Norma-Jean [14]

(2/3),=(1/2), 3,4
.
............................

4 0

2 years ago