3.5^2+2.6×3-6 anybody explain this please.
1 answer:
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Answer:
Since the p value is less than the significance level of 0.05 we have enough evidence to reject the null hypothesis in favor of the claim
And the best conclusion for this case would be:
b)The p-value is 0.008, indicating sufficient evidence for his claim.
Step-by-step explanation:
Information provided
represent the sample mean fould against
represent the sample standard deviation
sample size
represent the value that we want to test
represent the significance level for the hypothesis test.
t would represent the statistic (variable of interest)
represent the p value for the test (variable of interest)
System of hypothesis
We need to conduct a hypothesis in order to check if the true mean is higher than 11.5 fouls per game:
Null hypothesis:
Alternative hypothesis:
The statistic is given by:
(1)
The statistic is given by:
P value
The degreed of freedom are given by:
Since is a one side test the p value would be:
Since the p value is less than the significance level of 0.05 we have enough evidence to reject the null hypothesis in favor of the claim
And the best conclusion for this case would be:
b)The p-value is 0.008, indicating sufficient evidence for his claim.
