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Mamont248 [21]
3 years ago
15

there are three source of resistance in parallel circuit. Two of them are rated at 20 ohms, the other at 10 ohms. What is the ci

rcuits total resistance
Mathematics
1 answer:
Yanka [14]3 years ago
5 0
In paraller connection you can calculate the equivlant resistqnce from the relation :
1/R(equi) = 1/R1 + 1/R2 + 1/R3
1/R(equi) = 1/20 +1/20 + 1/10
1/R(equi) = 0.05+0.05+0.1 = 0.2
so, R(equi) = 5 ohms
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Consider the following quadratic function Part 3 of 6: Find the x-intercepts. Express it in ordered pairs.Part 4 of 6: Find the
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Answer:

The line of symmetry is x = -3

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Given a quadratic function, we know that the graph is a parabola. The general form of a parabola is:

y=ax^2+bx+c

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-x^2-6x-13=0

To solve this, we can use the quadratic formula:

x_{1,2}=\frac{-(-6)\pm\sqrt{(-6)^2-4\cdot(-1)\cdot(-13)}}{2(-1)}

And solve:

x_{1,2}=\frac{6\pm\sqrt{36-52}}{-2}x_{1,2}=\frac{-6\pm\sqrt{-16}}{2}

Since there is no solution to the square root of a negative number, the function does not have any x-intercept. The correct option is ZERO x-intercepts.

Part 4:

To find the y intercept, we need to find the value of y when x = 0:

y=-0^2-6\cdot0-13=-13

The y-intercept is at (0, -13)

Part 5:

Now we need to find two points in the parabola. Let-s evaluate the function when x = 1 and x = -1:

x=1\Rightarrow y=-1^2-6\cdot1-13=-1-6-13=-20x=-1\Rightarrow y=-(-1)^2-6\cdot(-1)-13=-1+6-13=-8

The two points are:

(1, -20)

(-1, -8)

Part 6:

Now, we can use 3 points to find the graph of the parabola.

We can locate (1, -20) and (-1, -8)

The third could be the vertex. We need to find the y-coordinate of the vertex. We know that the x-coordinate of the vertex is x = -3

Then, y-coordinate of the vertex is:

y=-(-3)^2-6(-3)-13=-9+18-13=-4

The third point we can use is (-3, -4)

Now we can locate them in the cartesian plane:

And that's enough to get the full graph:

8 0
1 year ago
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