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3 years ago

Is the square root of 2 a integer

Mathematics

2 answers:

Mkey [24]3 years ago

3 0

Answer:

Because √2 is not an integer (2 is not a perfect square), √2 must therefore be irrational. ... For a proof that the square root of any non-square natural number is irrational, see quadratic irrational or infinite descen

Step-by-step explanation:

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blondinia [14]3 years ago

3 0

Nope! ▫︎

It is irrational (it goes on for ever) ✩

Integers are finite numbers (zero+positive+negative numbers) ‣

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✥ ✴︎ ⭐︎ ✦

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the greater of two numbers is 1 less than 4 times the lesser. three times the lesser number is 4 less than the greater. find the

Komok [63]

<h2>Steps:</h2>

So for this, we will be doing a system of equations. Using the info from our question, our two equations are:

(let x = greater number and y = lesser number)

$x=4y-1\\3y=x-4$

Now, for this I will be using the substitution method. Since we know that x = 4y - 1, substitute that into the second equation:

$3y=4y-1-4$

From here we can solve for y. Firstly, combine like terms:

$3y=4y-5$

Next, subtract 4y on both sides of the equation:

$-y=-5$

Next, multiply both sides by -1:

$y=5$

Now that we know the value of y, substitute it into either equation to solve for x:

$x=4(5)-1\\x=20-1\\x=19\\\\3(5)=x-4\\15=x-4\\19=x$

<h2>Answer:</h2>

In short, <u>5 is the lesser number and 19 is the greater number.</u>

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asambeis [7]

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Brilliant_brown [7]

Answer:

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IgorC [24]

Answer:

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Step-by-step explanation:

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Is the square root of 2 a integer​

Is the square root of 2 a integer