Question

1. What is the value of x? Show all of your work.

Answer 1

AB^2 + BC^2 = AC^2
AB^2 + 6^2 = square root 117^2
AB^2 + 36 = 117

Now subtract 117 from both sides
AB^2 = 81
AB = square root 81 = 9
$\sqrt{81} = 9$
Therefore AB is 9 cms.