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3 years ago

1. What is the value of x? Show all of your work.

Mathematics

1 answer:

asambeis [7]3 years ago

3 0

AB^2 + BC^2 = AC^2
AB^2 + 6^2 = square root 117^2
AB^2 + 36 = 117

Now subtract 117 from both sides
AB^2 = 81
AB = square root 81 = 9
$\sqrt{81} = 9$
Therefore AB is 9 cms.

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BlackZzzverrR [31]

Answer: Probably A

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2 years ago

Choose at least three different careers you are interested in pursuing. Research the education level the career requires, the an

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Answer:

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Step-by-step explanation:

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3 years ago

Triangle ABC has vertices at A(−3, 4), B(4, −2), C(8, 3). The triangle is translated 4 units down and 3 units left. Which rule r

crimeas [40]

Option C: $(x, y) \rightarrow(x-3, y-4) ; (5,-1)$ is the coordinates of C after translation.

Explanation:

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Also, given that the triangle is translated 4 units down and 3 units left.

We need to determine the coordinates of the vertex C after translation.

The triangle is shifted 4 units down means subtracting 4 units from the y - coordinate of the graph.

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Also, the triangle is shifted 3 units left means subtracting 3 units from the x - coordinate of the graph.

Thus, it can be written as $x-3$

Thus, the translation is given by

$(x, y) \rightarrow(x-3, y-4)$

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3 years ago

Read 2 more answers

What is the value of i^n in if the remainder of n/4 is 2?

LekaFEV [45]

The value of ${i^n}$ is $\boxed{ - 1}$ if the remainder of $\dfrac{n}{4}$ is 2.

Further Explanation:

Given:

The remainder of $\dfrac{n}{4}$ is 2.

Explanation:

The sum of imaginary numbers and real numbers is known as the complex number.

The complex number can be expressed as follows,

$\boxed{z = a + ib}$

Here, a is the real part of the complex number and $\text{ib}$ is the imaginary part of the complex number.

$\sqrt{ - 1}$ can be denoted by i.

The value of ${i^2}$ is -1.

${i^2} = - 1$

The value ${i^3}$ can be obtained as follows,

$\begin{aligned}{i^3}&= {i^2} \times i\\&= - 1 \times i \\&= - i\\\end{aligned}$

The value ${i^4}$ can be obtained as follows,

$\begin{aligned}{i^4} &= {i^2} \times {i^2}\\&= - 1 \times - 1 \\&= 1\\\end{aligned}$

The value of ${i^n}$ is $\boxed{ - 1}$ if the remainder of $\dfrac{n}{4}$ is $2$ .

Learn more:

Learn more about inverse of the functionhttps://brainly.com/question/1632445.
Learn more about equation of circle brainly.com/question/1506955.
Learn more about range and domain of the function brainly.com/question/3412497

Answer details:

Grade: Middle School

Subject: Mathematics

Chapter: Complex numbers

Keywords: value, $i^ n$ , remainder, n/4, 2 quotient, divisor, complex number, imaginary number, real number, exponents, dividend, powers, -1, imaginary roots.

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2 years ago

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allsm [11]

Answer:

$3 \sqrt{5}$

Step-by-step explanation:

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the chord of length 12 can be splitted into two parts of 6 length each.

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The explanation is given in the picture

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