Answer : option B
the correct method to label a segment with endpoint E and endpoint F
The endpoints of the line are E and F
The Line starts at E and ends at F. The line will not extend after F
The line having end points are called as line segment
We represent a line segment by putting a line at the top
to label a segment with endpoint E and endpoint F, we use EF or FE and a line at the top
So answer is option B
Answer:
Hello,
Step-by-step explanation:
Roots are -2 and 4
y=k*(x+2)(x-4)
Vertex = (1,-9) is a point of the parabola
-9=k*(1+2)(1-4) ==> k=1
Equation of the parabola is y=(x+2)(x-4)
But you don' t have given the graphs !!!!
Find the line that is normal to the parabola at the given point
remember that normal means perpendicular
perpendicular lines have slopes that multiply to -1
we can use point slope form to write the equation of the line since we are given the point (1,0)
we just need the slope
take derivitive
y'=1-2x
at x=1
y'=1-2(1)
y'=1-2
y'=-1
the slope is -1
the perpendicular of that slope is what number we can multiply to get -1
-1 times what=-1?
what=1
duh
so
point (1,0) and slope 1
y-0=1(x-1)
y=x-1 is da equation
solve for where y=x-1 and y=x-x² intersect
set equatl to each other since equal y
x-1=x-x²
x²-1=0
factor difference of 2 perfect squares
(x-1)(x+1)=0
set to zero
x-1=0
x=1
we got this point already
x+1=0
x=-1
sub back
y=-1-(-1)²
y=-1-(1)
y=-1-1
y=-2
it intersects at (-1,-2)
Answer:It would be 8ft ??
Step-by-step explanation: 3ft = 8ft
