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AfilCa [17]
3 years ago
8

Show ur work and check it for both

Mathematics
1 answer:
Oksi-84 [34.3K]3 years ago
5 0

Answer:

7) is 26 8) is 20

30-4=26

16+4=20

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Sandy works at a clothing store. She makes $8 per hour plus earns 10% commission on her sales. She worked 70 hours over the last
Sindrei [870]
I would say $560. Good luck
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3 years ago
Dale cut a wire into 7 equal pieces. The wire was originally 7.84 meters long. How long is each piece?
ycow [4]
7.84 / 7 = 1.12 meters per piece <=
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3 years ago
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The plot below represents the function f(2):
Vinil7 [7]

Answer:

f(4) = 3

x = -1

Step-by-step explanation:

Line graphed shows a linear function.

Since this line passes through two points (4, 3) and (-1, 4)

Let the function is,

f(x) = mx + b

where 'm' = slope of the line

b = y-intercept of the line

Slope 'm' = \frac{y_2-y_1}{x_2-x_1}

               = \frac{4-3}{-1-4}

               = -\frac{1}{5}

f(x) = -\frac{1}{5}x+b

Since a point (4, 3) lies on the line,

f(4) = -\frac{1}{5}(4)+b

3 = -\frac{4}{5}+b

b = 3 + 0.8

b = 3.8

Therefore, f(x) = -0.2x + 3.8

For x = 4

f(4) = -0.2(4) + 3.8    

     = -0.8 + 3.8

     = 3.0

For f(x) = 4

4 = -0.2x + 3.8

0.2x = 3.8 - 4

x = \frac{-0.2}{0.2}

x = -1

5 0
3 years ago
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Solve the quadratic function by completing the square. What are the missing pieces in the steps? -32=2(x^2+10)
pychu [463]
-32+<u>50</u> =2(x^2+10x+25)
18=2(x+5)^2
9= (x+5)^2
+-<u /> <u>3</u> = x+5
x= -2 or x= <u>-8</u>
7 0
3 years ago
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Given point T(-6,-3) and point K(2,3), find the distance from point T to point K.​
navik [9.2K]

Answer:

d = 10

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Algebra II</u>

  • Distance Formula: d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Step-by-step explanation:

<u>Step 1: Define</u>

Point T (-6, -3)

Point K (2, 3)

<u>Step 2: Find distance </u><em><u>d</u></em>

Simply plug in the 2 coordinates into the distance formula to find distance <em>d</em>

  1. Substitute [DF]:                    d = \sqrt{(2+6)^2+(3+3)^2}
  2. Add:                                      d = \sqrt{(8)^2+(6)^2}
  3. Exponents:                           d = \sqrt{64+36}
  4. Add:                                      d = \sqrt{100}
  5. Evaluate:                              d = 10
7 0
3 years ago
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