Xy + 6e^y = 6e
taking first derivative :
<span>xy' + y + 6y(e^y)(y') = 0 </span>
<span>xy" + y' + y' + 6y'(e^y)(y') + 6yy(e^y)y' + 6y(e^y)y" = 0 </span>
<span>Put x = 0,
0 + 6e^y = 6e,
y = 1 </span>
<span>0 + 1 + 6(1)(y')e = 0,
Put y' = 0 </span>
<span>0 + 0 + 0 + 0 + 0 +6 ey" = 0,
y" = 0</span>
Answer:
7%
Step-by-step explanation:
15y+14=10y+12
15y-10y=12-14
5y= -2
y= -2/5
Answer:
283.495
Step-by-step explanation:
Answer:
-62
Step-by-step explanation:
-2 + (6)(-10) = -2 -60 = -62
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2 less than a product is 2 subtracted from the product, or -2 added to the product. A product is formed by multiplying the given numbers.
The product of 6 and -10 is 6×(-10) = -60. 2 less than that is -62.