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polet [3.4K]
2 years ago
7

Solve the inequality and show ur work please - 5x + 2) >5​

Mathematics
1 answer:
lakkis [162]2 years ago
8 0

Answer:

<h2>x <  -  \frac{3}{5}</h2>

Step-by-step explanation:

| - 5x + 2|  > 5 \\  - 5x > 5 - 2 \\  - 5x > 3 \\ x <  -  \frac{3}{5}

<h3>Hope it is helpful....</h3>
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Nookie1986 [14]
.764 in percentage form is 76.4%
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3 years ago
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Find the linear approximation of the function g(x) = 3 root 1 + x at a = 0. g(x). Use it to approximate the numbers 3 root 0.95
Virty [35]

Answer:

L(x)=1+\dfrac{1}{3}x

\sqrt[3]{0.95} \approx 0.9833

\sqrt[3]{1.1} \approx 1.0333

Step-by-step explanation:

Given the function: g(x)=\sqrt[3]{1+x}

We are to determine the linear approximation of the function g(x) at a = 0.

Linear Approximating Polynomial,L(x)=f(a)+f'(a)(x-a)

a=0

g(0)=\sqrt[3]{1+0}=1

g'(x)=\frac{1}{3}(1+x)^{-2/3} \\g'(0)=\frac{1}{3}(1+0)^{-2/3}=\frac{1}{3}

Therefore:

L(x)=1+\frac{1}{3}(x-0)\\\\$The linear approximating polynomial of g(x) is:$\\\\L(x)=1+\dfrac{1}{3}x

(b)\sqrt[3]{0.95}= \sqrt[3]{1-0.05}

When x = - 0.05

L(-0.05)=1+\dfrac{1}{3}(-0.05)=0.9833

\sqrt[3]{0.95} \approx 0.9833

(c)

(b)\sqrt[3]{1.1}= \sqrt[3]{1+0.1}

When x = 0.1

L(1.1)=1+\dfrac{1}{3}(0.1)=1.0333

\sqrt[3]{1.1} \approx 1.0333

7 0
3 years ago
|r|=-2 solve the equation and graph the solution if possible
S_A_V [24]
That bracket symbol, with an r in it, means "the absolute value of r". 
So r's absolute value is -2 meaning r is two units from zero
r= 2
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3 years ago
What is the x-intercept of the equation y=-5x+1,450?​
ladessa [460]

Substitute the value for y as 450

450=-5x+1

Solve for x

450-1=-5x

449=-5x

89.8=-x

x=-89.8

6 0
3 years ago
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Can someone help me on this question pls
andrew11 [14]

Answer:5.75

Step-by-step explanation: You are supposed to multiply you base and height which is 4.6 and 2.5 then divide by 2.

8 0
3 years ago
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