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s2008m [1.1K]
2 years ago
8

If x= -1 and y = -21, then xy – 5x =

Mathematics
1 answer:
aev [14]2 years ago
3 0

Answer:

a i think

Step-by-step explanation:

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Plz help i suck art math
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um 600?? I'm sorry if that's wrong

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3 years ago
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J.J.Bean sells a wide variety of outdoor equipment and clothing. The company sells both through mail order and via the internet.
melamori03 [73]

Answer:

99% confidence interval for the true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is [$(-31.82) , $12.02].

Step-by-step explanation:

We are given that a random sample of 16 sales receipts for mail-order sales results in a mean sale amount of $74.50 with a standard deviation of $17.25.

A random sample of 9 sales receipts for internet sales results in a mean sale amount of $84.40 with a standard deviation of $21.25.

The pivotal quantity that will be used for constructing 99% confidence interval for true mean difference is given by;

                      P.Q.  =  \frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}{s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }  ~ t__n_1_+_n_2_-_2

where, \bar X_1 = sample mean for mail-order sales = $74.50

\bar X_2 = sample mean for internet sales = $84.40

s_1 = sample standard deviation for mail-order purchases = $17.25

s_2 = sample standard deviation for internet purchases = $21.25

n_1 = sample of sales receipts for mail-order purchases = 16

n_2 = sample of sales receipts for internet purchases = 9

Also,  s_p =\sqrt{\frac{(n_1-1)\times s_1^{2}+(n_2-1)\times s_2^{2} }{n_1+n_2-2} }  =  \sqrt{\frac{(16-1)\times 17.25^{2}+(9-1)\times 21.25^{2} }{16+9-2} } = 18.74

The true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is represented by (\mu_1-\mu_2).

Now, 99% confidence interval for (\mu_1-\mu_2) is given by;

             = (\bar X_1-\bar X_2) \pm t_(_\frac{\alpha}{2}_)  \times s_p \times \sqrt{\frac{1}{n_1} +\frac{1}{n_2}}

Here, the critical value of t at 0.5% level of significance and 23 degrees of freedom is given as 2.807.

          = (74.50-84.40) \pm (2.807  \times 18.74 \times \sqrt{\frac{1}{16} +\frac{1}{9}})

          = [$-31.82 , $12.02]

Hence, 99% confidence interval for the true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is [$(-31.82) , $12.02].

5 0
3 years ago
Dawn works at the sponge factory and puts sponges in bags. She gets paid $0.12 for every sponge. If she got a paycheck for $864.
Ratling [72]

Answer:

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Step-by-step explanation:

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Determine if triangle OPQ and triangle RST are or are not similar, and, if they are, state which triangle similarity shortcut (A
murzikaleks [220]

Answer:

SAS Similarity

Step-by-step explanation:

ΔOPQ similar to ΔRST

∠Q  = ∠T

OQ : RT = 28 : 84 = 1 : 3

QP : TS  = 16 : 48 = 1 : 3

The measures of two sides of ΔOPQ are proportional to the measure of two side of ΔRST and their included angles are congruent.  The triangles are similar by SAS Similarity.

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Two and one ninth minus seven sixth equals
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.944
2 1/9 = 2.111
7/6 = 1.167
2.111-1.167= .944

4 0
2 years ago
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