All categories

3 years ago

Lesson 7 Using Distributive Property Area Assignment. pls help

Mathematics

1 answer:

dexar [7]3 years ago

3 0

Answer:

Step-by-step explanation:

1) 3*7

2) a*4

3) m*m

4) (4*x)+(4*1)

5) (7*d)+(7*4)

6) (y*y)+(y*3)

7) 1+x

8) d+4

9) y+3

11) Area as Sum: 7d+28, Area as Product 7(d+4)

12) Area as Sum: y(y)+3, Area as Product y(y+3)

13) 5m+10

14) 8y+16

15) -3m-12

16) a^2+3a

17) h^2 2h

18) 2m^2+8m

19)-2z-16

20)-4x^2-40

21) (12x)(60), Area as Sum: 12x+60, Area as Product 12(x+60)

22) (x)(4), Area as Sum: 5x+20, Area as Product 5(x+4)

You might be interested in

Will give Brainliest!!!

castortr0y [4]

Answer:

Step-by-step explanation:

if you plug 4 in for x it solves it

6 0

2 years ago

Read 2 more answers

TJ-Maxx offered a 36% discount off the original price of a head board. The amount of the discount is $9. What is the regular pri

jok3333 [9.3K]

The amount if the original cost of the head board is $12.24

5 0

2 years ago

The lengths of the legs of a right triangle are consecutive even integers. The hypotenuse is 58 inches. What is the sum of the l

miskamm [114]

Answer:

82 inches

Step-by-step explanation:

The difference between consecutive even integers is 2, thus

let the legs be n and n + 2

Using Pythagoras' identity in the right triangle

The square on the hypotenuse is equal to the sum of the squares on the other 2 sides, that is

n² + (n + 2)² = 58² ← expand and simplify left side

n² + n² + 4n + 4 = 3364 ( subtract 3364 from both sides )

2n² + 4n - 3360 = 0 ( divide all terms by 2 )

n² + 2n - 1680 = 0 ← in standard form

(n + 42)(n - 40) = 0 ← in factored form

Equate each factor to zero and solve for n

n + 42 = 0 ⇒ n = - 42

n - 40 = 0 ⇒ n = 40

But n > 0 ⇒ n = 40

and n + 2 = 40 + 2 = 42

Thus sum of legs = 40 + 42 = 82 inches

3 0

3 years ago

If y = kx, what is the value of k if y = 20 and x = 0.4? A)5 B)8 C)9.6 D)50

JulsSmile [24]

$\\ \sf\longmapsto y=kx$

$\\ \sf\longmapsto k=\dfrac{y}{x}$

put values

$\\ \sf\longmapsto k=\dfrac{20}{0.4}$

$\\ \sf\longmapsto k=50$

5 0

3 years ago

Read 2 more answers

Which ordered pairs are solutions to the inequality 2x+y>−4?

hichkok12 [17]

we will proceed to resolve each case to determine the solution

we have

$2x+y>-4$

$y>-2x-4$

we know that

If an ordered pair is the solution of the inequality, then it must satisfy the inequality.

case a) $(5,-12)$

Substitute the value of x and y in the inequality

$-12>-2*5-4$

$-12>-14$ ------> is True

therefore

the ordered pair $(5,-12)$ is a solution of the inequality

case b) $(-3,0)$

Substitute the value of x and y in the inequality

$0>-2*-3-4$

$0>2$ ------> is False

therefore

the ordered pair $(-3,0)$ is not a solution of the inequality

case c) $(-1,-1)$

Substitute the value of x and y in the inequality

$-1>-2*-1-4$

$-1>-2$ ------> is True

therefore

the ordered pair $(-1,-1)$ is a solution of the inequality

case d) $(0,1)$

Substitute the value of x and y in the inequality

$1>-2*0-4$

$1>-4$ ------> is True

therefore

the ordered pair $(0,1)$ is a solution of the inequality

case e) $(4,-12)$

Substitute the value of x and y in the inequality

$-12>-2*4-4$

$-12>-12$ ------> is False

therefore

the ordered pair $(4,-12)$ is not a solution of the inequality

Verify

using a graphing tool

see the attached figure

the solution is the shaded area above the line

The points A,C, and D lies on the shaded area, therefore the ordered pairs A,C, and D are solution of the inequality

7 0

3 years ago

Read 2 more answers