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butalik [34]
3 years ago
11

Lesson 7 Using Distributive Property Area Assignment. pls help

Mathematics
1 answer:
dexar [7]3 years ago
3 0

Answer:

Step-by-step explanation:

1) 3*7

2) a*4

3) m*m

4) (4*x)+(4*1)

5) (7*d)+(7*4)

6) (y*y)+(y*3)

7) 1+x

8) d+4

9) y+3

11) Area as Sum: 7d+28, Area as Product 7(d+4)

12) Area as Sum: y(y)+3, Area as Product y(y+3)

13) 5m+10

14) 8y+16

15) -3m-12

16) a^2+3a

17) h^2 2h

18) 2m^2+8m

19)-2z-16

20)-4x^2-40

21) (12x)(60), Area as Sum: 12x+60, Area as Product 12(x+60)

22) (x)(4), Area as Sum: 5x+20, Area as Product 5(x+4)

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1.3/4 - 5 3/7 <br> 2.-9 3/10 - 2/11
kodGreya [7K]
1)\\\\\frac{3}{4}-5\frac{3}{7}\\\\\frac{3}{4}-\frac{38}{7}\\\\\frac{3}{4}*\frac{7}{7}-\frac{38}{7}*\frac{4}{4}\\\\\frac{21}{28}-\frac{152}{28}\\\\\frac{-131}{28}\\\\-4\frac{19}{28}\\\\\\2)\\\\-9\frac{3}{10}-\frac{2}{11}\\\\\frac{-93}{10}-\frac{2}{11}\\\\\frac{-93}{10}*\frac{11}{11}-\frac{2}{11}*\frac{10}{10}\\\\\frac{-1023}{110}-\frac{20}{110}\\\\\frac{-1043}{110}\\\\-9\frac{53}{110}
3 0
3 years ago
Write an equation of a line that is parallel to y=2x-5 that passes through the point (2,6).
inessss [21]

Answer: Parallel lines have the same slope

y = 2x +b

Use the given point (2, 5)

5 = 2(2) +b

b = 5 -4 = 1

The equation of the line is

y = 2x +1

Note general form of the slope-intercept form of a line is y = mx +b, where m is the slope and b is the y-axis intercept

Step-by-step explanation:

3 0
3 years ago
Select all of the following that are quadratic equations.
kifflom [539]
A quadratic equation is one in which the highest exponent of x is 2.
7x^2+14x=0 is quadratic; the highest exponent is 2.
x³-3x²+1=0 is NOT quadratic.  The highest exponent of x is 3, not 2.
5x-7=0 is NOT quadratic.  The highest exponent of x is 1, not 2.
x²+3x-5=0 is quadratic; the highest exponent of x is 2.
x-5=9x+7 is NOT quadratic.  The highest exponent of x is 1, not 2.
x²-x=3x+7 is quadratic; the highest exponent of x is 2.
5 0
4 years ago
I'll. ark brainlyest and give a lot of points for answering this right ​
valina [46]

Answer:

\displaystyle T'(  2,4)

\displaystyle U'( 1,1)

\displaystyle S' ( 3,2)

Step-by-step explanation:

we current vertices of the given triangle

  • \displaystyle T( - 2,4)
  • \displaystyle U( - 1,1)
  • \displaystyle S ( - 3,2)

remember that,

\rm\displaystyle(x,y) \xrightarrow{ \rm reflection \:  over \: y - axis}( -  x,y)

so we obtain:

\rm\displaystyle \: T( - 2,4) \xrightarrow{ \rm reflection \:  over \: y - axis}T'(  2,4)

\rm\displaystyle \: U( - 1,1) \xrightarrow{ \rm reflection \:  over \: y - axis}U' ( 1,1)

\rm\displaystyle S( - 3,2) \xrightarrow{ \rm reflection \:  over \: y - axis}S'( 3,2)

6 0
3 years ago
Step bro what are you doing
RoseWind [281]

Answer: Blue was with you at electrical

Source: Trust me dude

5 0
3 years ago
Read 2 more answers
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