Answer:
K What's the problem?
Step-by-step explanation:
Weight of an grapefruit=weight of an orange+8% weight of an orange
weight of an apple=weight of an orange -10% weight of an orange
a.<span>By what percentage is the grapefruit heavier than the apple?
We should find the connection between grapefruit and an apple. We know the connection between the weight of a grapefruit and an orange, we know the connection between an orange and an apple, so this means we know the connection between a grapefruit and an apple.
</span>
weight of an grapefruit=weight of an <span>orange+8% weight of an orange
</span>weight of an orange=weight of an apple<span> +10% weight of an apple
</span>
-> weight of an grapefruit=weight of an apple+10% weight of an apple + 8%(weight of an apple+10% weight of an apple)= weight of an apple + 18% weight of an apple + 2% weight of an apple= <span>weight of an apple + 20% weight of an apple
</span><span>b.By what percentage is the apple lighter than the grapefruit?
</span>weight of an grapefruit=weight of an apple + 20% weight of an apple<span>
</span>
-> The apple ts 20% lighter than the grapefruit.
Answer:
Name a transversal - i
Name all corresponding angles -
6 = 8
1 = 3
2 = 4
5 = 7
Name all alternate exterior angles -
1 = 5
4 = 8
Answer:
125 deg
Step-by-step explanation:
Keep these three rules in mind:
1) A central angle (vertex is the center of the circle) has the same measure as the arc it intercepts.
2) The measure of an inscribed angle (vertex is point on circle) is half the measure of the intercepted arc.
3) Opposite angles of a rectangle inscribed in a circle are supplementary.
110 deg is a central angle.
By rule 1), the arc intercepted by the central angle 110 deg also measures 110 deg.
a is an inscribed angle that intercepts an arc of 110 deg.
By rule 2), the measure of an inscribed angle is half the measure of the intercepted arc.
angle a measures 55 deg.
Rule 3) Angles a and b are supplementary.
a + b = 180
55 + b = 180
b = 125