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Natasha2012 [34]
2 years ago
11

Given the values of the linear functions f (x) and g(x) in the tables, where is (f – g)(x) positive?

Mathematics
1 answer:
LuckyWell [14K]2 years ago
7 0

From the tables, and definitions of functions, it is found that the function (f - g)(x) is positive in the interval (–∞, –2).

--------------------

  • The function (f - g)(x) is given by: (f - g)(x) = f(x) - g(x)
  • Thus, it will be positive if: f(x) > g(x)
  • Looking at the table, and considering that it is a linear function, we have that f(x) > g(x) if x < -2.
  • Thus, (f - g)(x) is positive in the interval (–∞, –2).

A similar problem is given at brainly.com/question/24388889

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The sum of two consecutive odd integers is 20 less than four times the smaller of the two integers. Which the following equation
Rudiy27

Answer:

consecutive = x+x+2

x+x+2 = 4x-20

2x+2=4x-20

2=2x-20

22=2x

x=11

Numbers are 11,13.

Hope this helps plz hit the crown :D

8 0
3 years ago
Replace ? with =, &gt;, or &lt; to make the statement true. 12 ÷ 4 + 13 ? 2 + 22 ÷ 2
bogdanovich [222]

Answer:

>

Step-by-step explanation:

On the left side, we divide first: 12/4=3

On the left side, we get 3+13, which equals 16.

On the right side, we also divide first: 22/2=11

On the right side, we get 11+2, which equals 13.

We know that 16 is larger than 13, so  

12 ÷ 4 + 13 > 2 + 22 ÷ 2

Hope this helps!

8 0
3 years ago
Rectangle J'K'L'M' shown on the grid is the image of rectangle JKLM after transformation. The same transformation will be applie
timama [110]

Answer:

  • (16, 7)

Step-by-step explanation:

Given rectangle JKLM

As per graph, the rectangle J'K'L'M' is the transformation of JKLM

Based on one of the points we can calculate the transformation rule:

<u>Let's use points K and K'</u>

  • K((-4, -8) → K'(6, -5)
  • 6 - (-4) = 10
  • -5 - (-8) = 3

<u>So the rule is </u>

  • (x', y') → (x + 10, y +3)

<u>Trapezoid STUV:</u>

  • Using point T(6, 4)

<u>Applying same rule:</u>

  • T' = (6 + 10, 4 +3) = (16, 7)
6 0
3 years ago
What’s is part A?? .....
bixtya [17]

Answer:

A. 3

B. 4

C. 1

D. 2

Step-by-step explanation:

Consider all equations:

A. y=x^2 -6x+8

This is the equation of parabola with vertex at point

x_v=\dfrac{-b}{2a}=\dfrac{-(-6)}{2\cdot 1}=3\\ \\y_v=3^2-6\cdot 3+8=9-18+8=-1

The y-intercept is at point

x=0\\ \\y=0^2-6\cdot 0+8=8

Since

x^2 -6x+8=x^2-4x-2x+8=x(x-4)-2(x-4)=(x-2)(x-4),

the x-intercepts are at points (2,0) and (4,0)

The leading coefficient is 1 > 0, then the parabola opens upwards.

Hence, the graph of this parabola is 3.

B. y=(x-6)(x+8)

This parabola has two x-intercepts at points (6,0) and (-8,0).

The leading coefficient is 1 > 0, then the parabola opens upwards.

The only possible choice is parabola 4.

C. y=(x-6)^2+8

This parabola has the vertex at point (6,8), opens upwards, therefore does not intersect the x-axis.

The graph of this parabola is 1.

D. y=-(x+8)(x-6)

This parabola has two x-intercepts at points (6,0) and (-8,0).

The leading coefficient is -1 > 0, then the parabola opens downwards.

The only possible choice is parabola 2.

4 0
3 years ago
Read 2 more answers
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vovangra [49]

Answer:

$5

Step-by-step explanation:

subtract

8 0
3 years ago
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