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kari74 [83]
3 years ago
12

How do i reduce a shape by using the scale factor 2:1

Mathematics
1 answer:
bearhunter [10]3 years ago
3 0

Answer: i think you're talking about dilations and there are specific formulas depending on the situation.

for example: the dilation of (x,y) is (-1/2x, -1/2y).

you'd probably need to subtract 2 from whatever measurements of the shape you're working with. i'm not completely sure though

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7 inches by 4 inches. the frame is created from 10 square inches of framing material
coldgirl [10]
74 inches whskdnsaskfis
5 0
3 years ago
Cone A has a radius of 12 inches and Cone B has a radius of 30 inches. If the cones are similar and the volume of Cone A is 48 f
Vika [28.1K]

Answer:

750 ft^3

Step-by-step explanation:

Given that the cones are similar, the first step would be to determine their linear scale factor; That is the ratio of their radii;

\frac{RadiusB}{RadiusA}=\frac{30}{12}=2.5

The next step is to determine the volume scale factors. Since the linear scale factor is 2.5, the volume scale factor would be;

volume scale factor = (linear scale factor)^3

                                 = 2.5^3 = 125/8

The volume of Cone B will thus be;

volume of Cone A * volume scale factor = 48 * 125/8 = 750 ft^3

6 0
3 years ago
Cardiothoracic surgeon jacajacara Coleman MD and cardiovascular surgeon Jurnee Wright MD decide to purchase and office space tog
tia_tia [17]

<u>Answer:</u>

Jacara and Jurnee have $ 710000 and $ 390000 respectively as amounts.

<u>Step-by-step explanation:</u>

Let, Jacara's and Jurnee's amounts be $ x and $ y respectively.

According to the question,

20 % of the total amount = $ 220,000

So, total amount = $220,000 \times 5

                           =$ 1100,000

According to the question,

x + y = 1100,000 -----------(1)

and, x = 2 \times y - 70000-----------(2)

from (1), x = 1100,000 - y--------------(3)

Deducting (2) from (3),

3 \times y = 1170,000

⇒  y = \frac{1170000}{3}

⇒ y = 390000-------------------(4)

from (1) and (4),

x = 1100,000 - 390000

 = 710000---------------(5)

6 0
3 years ago
A 11-inch candle is lit and burns at a constant rate of 1.3 inches per hour. Let t represent the number of hours since the candl
dem82 [27]

Answer:

f(t)= 11 in - 1.3 in/h *t

Step-by-step explanation:

defining the length of the candle as L , then since the candle burns at a constant rate , then

-dL/dt = 1.3 in/h = a

therefore

-∫dL = a∫dt

-L(t)=a*t + C , C=constant

at t=0 , the length of the candle is L₀= 11 in ,thus

-L₀=a*0 + C →  C= -L₀

replacing the value of C

-L(t)=a*t - L₀

L(t) = L₀ - a*t = 11 in - 1.3 in/h *t

then

f(t)= 11 in - 1.3 in/h *t

8 0
3 years ago
11. Solve the inequality. Show your work.<br> |r + 3| ≥ 7
brilliants [131]
Answer:

<span>r≤−10∪r≥4</span>

Explanation:

<span><span>|<span>r+3</span>|</span>≥7</span>

SOLUTION 1
<span>r+3≥7</span>
<span>r≥4</span>

SOLUTION 2

<span>r+3≤−7</span>
<span>r≤−10</span>

Since the two inequalities do not intersect when graphed, the solution set is

<span>r≤−10∪r≥<span>4 </span></span>

5 0
3 years ago
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