All categories

2 years ago

How do i reduce a shape by using the scale factor 2:1

Mathematics

1 answer:

bearhunter [10]2 years ago

3 0

Answer: i think you're talking about dilations and there are specific formulas depending on the situation.

for example: the dilation of (x,y) is (-1/2x, -1/2y).

you'd probably need to subtract 2 from whatever measurements of the shape you're working with. i'm not completely sure though

You might be interested in

What equations show you how to find 16-9

kirill [66]

You can do:

16 - 10 and then + 1 (thats 7)

9+ ? is 16 ? ( 7)

7 0

3 years ago

Read 2 more answers

Find j. 6 + 2(3j – 2) = 4(1 + j)

Sindrei [870]

Answer:

j=1

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Twice the sum of x and 5

SIZIF [17.4K]

I believe it would be x+5^2

3 0

3 years ago

Read 2 more answers

How can I factor 5x^2 + 26x - 24 = 0 using the completing the square method.

kifflom [539]

<h2><u>QUADRATIC EQUATION</u></h2>

<h2> $\mathbb{ANSWER:}$ </h2>

$\bold{x = 0.8 \: } \: \sf \: {\color{grey}or} \: \: \: \bold{ x= \frac{4}{5} } \\$

$\bold{x = - 6}$

— — — — — — — — — —

<h3>Step-by-step explanation:</h3>

<u>How can </u><u>we</u><u> factor 5x^2 + 26x - 24 = 0 using the completing the square </u><u>method?</u>

Let's solve your equation step-by-step.

$\bold{Given \: Equation: \color{brown} 5x²+26x-24=0}$

First, add 24 to both sides.

$\bold{5x²+26x-24 - \purple{ 24} = 0 + \purple{24}}$

$\bold{ \implies \: 5x²+26x = 24 }$

Since the coefficient of 5x² is 5, divide both sides by 5.

$\bold{ \frac{5 {x}^{2} + 26x }{5} = \frac{24}{5} } \\$

$\bold{ \implies \: {x}^{2} + \frac{26}{5} x = \frac{24}{5} } \\$

The coefficient of 26/5x is 26/5. So, let b=26/5.

Then we need to add (b/2)²=169/25 to both sides to complete the square.

Add 169/25 to both sides.

$\bold{ {x}^{2} + \frac{26}{5} x + \frac{ \purple{169}}{ \purple{25}}= \frac{24}{5} + \frac{ \purple{169}}{ \purple{25}} } \\$

$\bold{ \implies \:\bold{ {x}^{2} + \frac{26}{5} x + \frac{ 169}{ {25}}= \frac{289}{25} } } \\$

Factor the left side.

$\bold{(x + \frac{13}{5} ) {}^{2} = \frac{289}{25} } \\$

Take square root.

$\bold{x + \frac{13}{5} = ± \: \sqrt{ \frac{289}{25} }} \\$

Then, add (-13)/5 to both sides.

$\bold{x + \frac{13}{5} + \frac{\purple{ - 13} }{\purple{ 5}} = \frac{{ - 13} }{{ 5}} ± \: \sqrt{ \frac{289}{25}}} \\$

$\bold{ \: x = \frac{ - 13}{5} ± \sqrt{ \frac{289}{25} } } \\$

$\implies \: \underline{ \boxed{ \bold{ \frac{4}{5} } \sf \: \: or \: \: \bold{ x = - 6}}} \\$

_______________❖_______________

3 0

2 years ago

Read 2 more answers

Can someone plz help me doing this :D

Mars2501 [29]

Ok so the first thing you would do is input the number where The variables are in the equation so 8^2-5(4)/4

6 0

3 years ago