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Natali [406]
3 years ago
14

(1 point) For function f(x) = -3x2 + 29x - 40,

Mathematics
1 answer:
MaRussiya [10]3 years ago
8 0

×1=5/3, multiplicity 1; ×2=8 multiplicity 1

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Barry's deck of cards contains 40 blue cards and 70 red cards. Max's deck of cards contains the same number of blue cards, but t
RideAnS [48]

Since Max's deck of cards contains the same number of blue cards as Barry's,

letting x as the number of red cards in Max's deck of card

40 / x = 8 / 9

Solving for x

360 = 8x

x = 45


There are a total of 40 + 45 = 85 cards in Barry's deck of cards


7 0
4 years ago
Please help 14 points
ELEN [110]

Answer:

3 over 8 (0.375)

8 0
3 years ago
Which of the lines, if any, are parallel
Oksana_A [137]

Answer:

Line b and c

Step-by-step explanation:

5 0
3 years ago
Someone help me please.
mrs_skeptik [129]

Step-by-step explanation:

f(x) = -0.01x² + 0.7x + 6.1

a) f(x) is a downward facing parabola, so the maximum height is at the vertex.  The vertex of a parabola can be found using x = -b/(2a).

x = -0.7 / (2 × -0.01)

x = 35

f(35) = -0.01(35)² + 0.7(35) + 6.1

f(35) = 18.35

The maximum height is 18.35 feet.

b) The maximum horizontal distance is when the ball lands, or when f(x) = 0.

0 = -0.01x² + 0.7x + 6.1

0 = x² − 70x − 610

Solve with quadratic formula:

x = [ -b ± √(b² − 4ac) ] / 2a

x = [ -(-70) ± √((-70)² − 4(1)(-610)) ] / 2(1)

x = (70 ± √7340) / 2

x = 35 ± √1835

x = -7.84, 77.84

x can't be negative, so x = 77.84.  The ball's maximum horizontal distance is 77.84 feet.

c) When the ball is first launched, x = 0.  The height at that position is:

f(0) = 6.1

The ball is launched from an initial height of 6.1 feet.

7 0
3 years ago
HELP ME PLEASE WITH 1,2 AND 3 PLEASE DON'T TAKE LONG TO RESPOND !!​
soldi70 [24.7K]

Answer:

1. -19x

3. 23 -  8x

5. -18x + 2y

Step-by-step explanation:

first: 3x - x = 2x

2x - 22x = -20x

-20x + x = -19x

second one:

8 - (-15) = 23

12x - 20x = -8 x

23 - 8x

third:

-10x - 8x = -18x

3y - y = 2y

-18x + 2y

6 0
3 years ago
Read 2 more answers
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