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Firdavs [7]
2 years ago
15

color%7Bred%7D%20Question%7D%7D%7D%7D%20" id="TexFormula1" title=" \huge{\green}\fcolorbox{blue}{cyan}{\bf{\underline{\red{\color{red} Question}}}} " alt=" \huge{\green}\fcolorbox{blue}{cyan}{\bf{\underline{\red{\color{red} Question}}}} " align="absmiddle" class="latex-formula">
\mathfrak \orange{ Refer \: To \: Attachment}
​

Mathematics
1 answer:
MariettaO [177]2 years ago
5 0

\qquad\qquad\huge\underline{{\sf Answer}}

Let's find out the gradient (Slope " m ") of line q ;

\qquad \sf  \dashrightarrow \:m = \dfrac{y_2 - y_1}{x_2 - x_1}

\qquad \sf  \dashrightarrow \:m = \dfrac{4 - 0}{0 - 1}

\qquad \sf  \dashrightarrow  \:m =  - 4

Now, since we already know the gradient let's find of the equation of line by using its Slope and one of the points using point slope form of line :

\qquad \sf  \dashrightarrow \:y - 4 = m(x - 0)

\qquad \sf  \dashrightarrow \:y = mx + 4

Now, plug in the value of gradient ~

\qquad \sf  \dashrightarrow \:y =  - 4x + 4

here we can clearly observe that, the Area under the curve can easily be represented as :

\qquad \sf  \dashrightarrow \:y <  - 4x + 4

Since, all the values of y that lies in the shaded region is smaller than the actual value of y for the corresponding values of x in the equation of line q

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Please help my finals
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hope it helped :3

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