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tensa zangetsu [6.8K]
3 years ago
5

Write in numerical expression. 3 less than the difference between 5 and -6

Mathematics
1 answer:
Soloha48 [4]3 years ago
6 0

Answer:

3 -(5 -(-6))

Step-by-step explanation:

The difference between 5 and -6 is 5 -(-6). And "less than" is just another way of saying "minus".

So 3 - (5 -(-6)).

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Paige rolls a number cube sixty-four times. The number 4 comes up fourteen times. The number 3 comes up six times. Rounded to th
3241004551 [841]

Answer:

31%

Step-by-step explanation:

To determine the probability of obtaining 3 or any number in a roll, we divide the number of outcomes with the sample space.

           probability of 3 :    n = 6/64 = 3/32 = 0.09375

           probability of 4 :    n = 14/64 = 7/32 = 0.21875

Since, we use the conjuction "or", we therefore add up these probabilities. 

                     n = 5/16 or 0.3125

Hope this Helps

6 0
4 years ago
0.4(.0.3x-1)=2+0.75x
Korolek [52]
This is not a correct equitation
7 0
3 years ago
Read 2 more answers
1. Simplify the expression. Assume that
ololo11 [35]

Answer:

b. 6|x|

Step-by-step explanation:

√(36x²) = √36√(x²)= 6|x|

Because √ from the number can be only positive.

5 0
3 years ago
Write an equasion of the line in point-slope form that passes through the points (-16, 8) (4,2)
xeze [42]
You start by finding the slope :  y2 - y1 / x2 - x1

                                                 2 - 8 /  4 - (-16)
                                                   
                                                  - 6 / 20
                      
                                           m =  - 3 / 10 

Point slope form :  y - y1 = m( x- x1 )

           You can pick either of the coordinates and substitute them in

 POINT SLOPE FORM EQUATION   : y - 8 = -3/10 ( x + 16 )

5 0
3 years ago
What is the justification for the first step in proving the formula for factoring the sum of cubes?
Anna11 [10]

Explanation:

The formula isnt correctly written, it should state:

a^3+b^3 = (a+b)(a^2-ab+b^2)

You have to start from (a+b)(a^2-ab+b^2)  and end in a³+b³. On your first step, you need to use the distributive property.

(a+b)(a^2-ab+b^2) = a*(a^2-ab+b^2) + b*(a^2-ab+b^2)

This is equal to

a*a^2-a*(ab) + a*b^2 + b*a^2-b*(ab) + b*b^2 = a^3 - a^2b + ab^2 +ba^2 -b^2a +b^3

Note that the second term, -a²b, is cancelled by the fourth term, ba², and the third term, ab², is cancelled by the fifht term, -b²a. Therefore, the final result is a³+b³, as we wanted to.

5 0
4 years ago
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