Given:
13/8
First you have to see how many times 8 can go into the number 13. If you look, 8 can only go into 13 one time, leaving 5 left over.
13-8 = 5
1 with 5 left over
(Rather than writing 8/8, you must simplify to 1 to make it less redundant)
Since there is 5 left over from 8, you would then place it into the numerator place to get:
1 5/8
I hope this helps!
Answer x=63
Step-by-step explanation:
Answer:
3/5 X 3 1/2 = 3/5 X 7/2 = 21/10 = 2.1 in²
Step-by-step explanation:
Answer:
![cos(\pi)=-1](https://tex.z-dn.net/?f=cos%28%5Cpi%29%3D-1)
Step-by-step explanation:
![f(x)=cos (x)](https://tex.z-dn.net/?f=f%28x%29%3Dcos%20%28x%29)
State that the values where cos x is minimum:
![x=\pi +2\pi n, n\in \mathbb{Z}](https://tex.z-dn.net/?f=x%3D%5Cpi%20%2B2%5Cpi%20n%2C%20n%5Cin%20%5Cmathbb%7BZ%7D)
![cos(0)=1\\](https://tex.z-dn.net/?f=cos%280%29%3D1%5C%5C)
![$cos\left(\frac{\pi}{4} \right)=\frac{\sqrt{2} }{2} $](https://tex.z-dn.net/?f=%24cos%5Cleft%28%5Cfrac%7B%5Cpi%7D%7B4%7D%20%5Cright%29%3D%5Cfrac%7B%5Csqrt%7B2%7D%20%7D%7B2%7D%20%24)
![$cos\left(\frac{\pi}{2} \right)=0 $](https://tex.z-dn.net/?f=%24cos%5Cleft%28%5Cfrac%7B%5Cpi%7D%7B2%7D%20%5Cright%29%3D0%20%24)
![cos(\pi)=-1](https://tex.z-dn.net/?f=cos%28%5Cpi%29%3D-1)
![$cos\left(\frac{3\pi}{2} \right)=0 $](https://tex.z-dn.net/?f=%24cos%5Cleft%28%5Cfrac%7B3%5Cpi%7D%7B2%7D%20%5Cright%29%3D0%20%24)