Question

A 60 kg person runs up a 30° ramp with a constant acceleration. She starts from rest at the bottom of the ramp and covers a distance of 15 m up the ramp in 5.8 s. What instantaneous power (in W) was she exerting at t = 4.0 s?

Answer 1

We have that the instantaneous power is

$P=1239.6W$

From the question we are told that

A 60 kg person runs up a 30° ramp

distance of 15 m up the ramp in 5.8 s.

t = 4.0 s?

Generally the equation for the Force  is mathematically given as

$F-mgsin\theta=ma\\\\F-60*9.8*sin30=60*a$

Where

$s=ut+1/2at^2\\\\15=+0.5*a*5.8^2\\\\\a=0.891$

Therefore

$F=60(0.891)+294\\\\F=347.5$

Where

$v=u+at\\\\v=3.567$

Now

$P=f*v\\\\P=347.50*3.567$

$P=1239.6W$

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