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Goryan [66]
3 years ago
9

A 60 kg person runs up a 30° ramp with a constant acceleration. She starts from rest at the bottom of the ramp and covers a dist

ance of 15 m up the ramp in 5.8 s. What instantaneous power (in W) was she exerting at t = 4.0 s?
Physics
1 answer:
Sladkaya [172]3 years ago
7 0

We have that the instantaneous power is

P=1239.6W

From the question we are told that

A 60 kg person runs up a 30° ramp

distance of 15 m up the ramp in 5.8 s.

t = 4.0 s?

Generally the equation for the Force  is mathematically given as

F-mgsin\theta=ma\\\\F-60*9.8*sin30=60*a

Where

s=ut+1/2at^2\\\\15=+0.5*a*5.8^2\\\\\a=0.891\\\\

Therefore

F=60(0.891)+294\\\\F=347.5

Where

v=u+at\\\\v=3.567

Now

P=f*v\\\\P=347.50*3.567

P=1239.6W

For more information on this visit

brainly.com/question/21231013?referrer=searchResults

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