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3 years ago

Solve for x 8x+2=42 what is the answer?

Mathematics

2 answers:

marta [7]3 years ago

4 0

<h3>Answer :</h3>

x = 5

Step-by-step explanation:

<h3>: Given equation </h3><h3> • 8x + 2 = 42 </h3><h3> 8x = 42 – 2</h3><h3> 8x = 40</h3><h3> x = 40/8 = 5</h3><h3> x = 5</h3>

nata0808 [166]3 years ago

4 0

Answer:

Hi, There! I'm here to help! :)

<u><em>The Correct Answer is x = 5</em></u>

Step-by-step explanation:

Here's your Equation below <3

8x + 2 = 42

8x = 42 – 2

8x = 40

x = 40/8 = 5

x = 5

<em>Hope this helps!</em>

<em />

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A new cell tower is being constructed and needs a guy-wire connected 180 feet up the tower and it needs to make an angle of 52°

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Step-by-step explanation:

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2 years ago

Suppose that the sample standard deviation was s = 5.1. Compute a 98% confidence interval for μ, the mean time spent volunteerin

NISA [10]

Answer:

The 95% confidence interval would be given by (5.139;5.861)

Step-by-step explanation:

1) Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size

2) Confidence interval

Assuming that $\bar X =5.5$ and the ranfom sample n=1086.

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=1086-1=1085$

Since the Confidence is 0.98 or 98%, the value of $\alpha=0.02$ and $\alpha/2 =0.01$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.01,1085)".And we see that $t_{\alpha/2}=2.33$

Now we have everything in order to replace into formula (1):

$5.5-2.33\frac{5.1}{\sqrt{1086}}=5.139$

$5.5+2.333\frac{5.1}{\sqrt{1086}}=5.861$

So on this case the 95% confidence interval would be given by (5.139;5.861) We are 98% confident that the mean time spent volunteering for the population of parents of school-aged children is between these two values.

5 0

3 years ago