Y=1/x is a reciprocal function & its shape is a special hyperbola with one branch located in the 1st Quadrant and the second in the 3dr Quadrant and both are symmetric about the origin O.
If a> 1 → y=a/x and the 2 branches are equally stretched upward & downward
about the center O.
If 0 < a < 1→y =a/x, the 2 branches are equally stretched downward and upward about the center O.
If a<0, then the 2 legs are in the 2nd and 4th Quadrant respectively
<em><u>The least amount of money you would need to invest per month is; $335</u></em>
<em><u>The anticipated rate of return on your investments is; 7%</u></em>
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- Amount to have been saved at the end of 10 years ≥ $40,000
Number of years of savings = 10 years.
- We want to find out the least amount to be invested per month.
There are 12 months in a year. Number of months in 10 years = 10 × 12 = 120 months.
- Thus, amount to be saved monthly = 40000/12 = $333.33
- Since the minimum amount he wants to save after 10 years is $40000, then we need to approximate the monthly savings in order.
Thus;
Monthly savings ≈ $335
- Now, for the anticipated rate of return on the investment, we know from S & P's that the benchmark on good rate of return for investment is a minimum of 7%.
- From online calculator, the worth of the investment after 10 years based on 7% rate of return yearly would be $57626.
Read more at; brainly.com/question/9187598
Answer:
Slope=-1
Step-by-step explanation:
Slope=y1-y2/x1-x2
Where (X1,y1)(0,8) and (X2,y2) (4,4)
Slope=8-4/0-4
=4/-4
=-1
So slope is -1
When you see the subtraction<span> (</span>minus<span>) sign followed by a </span>negative<span> sign, turn the two signs into a plus sign. Thus, instead of </span>subtracting<span> a </span>negative<span>, you're adding a </span>positive<span>, so you have a simple addition problem.</span>
I'm assuming there's a chart, but if there isn't,
The population will continue to increase and decrease, as the population will grow until it's reached its carrying capacity, and then decrease because there aren't enough resources, and then increase, then decrease, etc.
