Question

Julio started biking to the park traveling 8 mph, after some time the bike got a flat so Julio walked the rest of the way, traveling 7 mph. If the total trip to the park took 7 hours and it was 52 miles away, how long did julio travel at each speed?

Answer 1

Answer:

Julio travel 3 hours by biking and 4 hours by walking.

Step-by-step explanation:

Given:

Julio started biking to the park traveling 8 mph, after some time the bike got a flat so Julio walked the rest of the way, traveling 7 mph.

If the total trip to the park took 7 hours and it was 52 miles away.

Now, to find the time Julio travel at each speed.

The speed travelled by the bike = 8 mph.

The speed travelled by the walking = 7 mph.

Let the time Julio travel with bike be $x.$

And the time Julio travel by walking be $y.$

As, given Julio started biking to the park traveling, after some time the bike got a flat so Julio walked the rest of the way,

Thus, the total time taken:

$x+y=7$

$y=7-x\ \ \ .......(1)$

So, the distance travelled by bike:

Speed × time

$8\times x=8x$

And, the distance travelled by walking:

Speed × time

$7\times y=7y$

Now, the total distance travelled by Julio:

$8x+7y=52$

Substituting the value of $x$ from equation (1) we get:

$8x+7(7-x)=52$

$8x+49-7x=52\\\\x+49=52$

Subtracting both sides by 49 we get:

$x=3.$

The time Julio travelled with bike = 3 hours.

Now, to get the time Julio travelled by walking by substituting the value of $x$:

$y=7-x\\\\y=7-3\\\\y=4\ hours.$

The time Julio travelled by walking = 4 hours.

Therefore, Julio travel 3 hours by biking and 4 hours by walking.