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3 years ago

Simplify the following expression. 7x- 8+2x5x11

Mathematics

1 answer:

Alborosie3 years ago

4 0

Answer:110x^2+7x-8

Step-by-step explanation:

7x- 8+2x5x11

7x-8+110x^2

reoder the terms

110x^2+7x-8

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Which choice best satisfies the formula for the area of a square whose sides are s inches long?

klasskru [66]

The area of the square whose sides is s inches long will be given by:
Area=length×width
Length=s inches
width=s inches
thus:
the area of the squares will be:
Area=s×s=s² sq. inches

Thus the correct answer is:
area=s² sq. in

8 0

3 years ago

Use the quadratic formula to solve the equation if necessary round to the nearest hundredth x^2+x-30=0

yaroslaw [1]

Answer:

(x-5)(x+6)=0

Step-by-step explanation:

hehe i doing the smae unit rn.

if a=1 (which it does do ac factoring)

you need two numbers that multiply to -30 and add to 1. those numbers are 5 and -6.

substitute 1x for -5x + 6x.

group the numbers into pairs and find their gcf's

x(x-5) 6(x-5)

since the parenthesis r the same yo only need one. Now you need to put x and 6 in a parenthesis.

FINAL: (x-5)(x+6) hope this helps

6 0

4 years ago

Consider the functions f and g defined by \[f(x) = \sqrt{\dfrac{x+1}{x-1}}\qquad\qquad\text{and}\qquad\qquad g(x) = \dfrac{\sqrt

tino4ka555 [31]

Answer:

The given functions are not same because the domain of both functions are different.

Step-by-step explanation:

The given functions are

$f(x)= \sqrt{\dfrac{x+1}{x-1}}$

$g(x) = \dfrac{\sqrt{x+1}}{\sqrt{x-1}}$

First find the domain of both functions. Radicand can not be negative.

Domain of f(x):

$\dfrac{x+1}{x-1}>0$

This is possible if both numerator or denominator are either positive or negative.

Case 1: Both numerator or denominator are positive.

$x+1\geq 0\Rightarrow x\geq -1$

$x-1\geq 0\Rightarrow x\geq 1$

So, the function is defined for x≥1.

Case 2: Both numerator or denominator are negative.

$x+1\leq 0\Rightarrow x\leq -1$

$x-1\leq 0\Rightarrow x\leq 1$

So, the function is defined for x≤-1.

From case 1 and 2 the domain of the function f(x) is (-∞,-1]∪[1,∞).

Domain of g(x):

$x+1\geq 0\Rightarrow x\geq -1$

$x-1\geq 0\Rightarrow x\geq 1$

So, the function is defined for x≥1.

So, domain of g(x) is [1,∞).

Therefore, the given functions are not same because the domain of both functions are different.

4 0

4 years ago

Calculate the length of the side BC. Using pythagoras

o-na [289]

Answer:

10m

Step-by-step explanation:

A^2+B^2=C^2

6^2+8^2=C^2

36+64=C^2

100=C^2

10=C

3 0

3 years ago

Read 2 more answers

98% of the mules who were surveyed said the stubborness was a good trait. if 343 mules gave this response, how many were surveye

g100num [7]

350 mules because if you do the proportion

7 0

3 years ago