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Sergeu [11.5K]
3 years ago
15

5(2x-3) –3(x+4)/9?

Mathematics
1 answer:
kvv77 [185]3 years ago
8 0

Answer:

b

Step-by-step explanation:

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What is the area of the gray triangle shown?<br>​
DanielleElmas [232]

Answer:

The area of the triangle is basically half the area of the square, so we only need to find the area of the square and divide it by 2:

S = (15 · 15)/2 = 112.5 (square units)

5 0
3 years ago
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Find the measure of line f and g
kiruha [24]

In this case we use intersecting secant theorem  

According to this theorem, GF*GE = GH*GA

So,we plug in the values

(x-3)*(x-3+9) =(x-2)*(x-2+6)

(x-3)*(x+6) =(x-2)*(x+4)

x^2 +6x -3x -18 =x^2 +4x -2x -8

x^2 +3x -18 =x^2 +2x -8

x^2 +3x -18 -x^2 -2x +8 =0

x -10 =0

x=10

So,FG =x-3 = 10-3 =7

6 0
3 years ago
Consider the system of equations:
vodka [1.7K]

Answer:

(x, y) = (5, 1)

Step-by-step explanation:

To <em>eliminate</em> x, you can double the second equation and subtract the first.

... 2(x +4y) -(2x -3y) = 2(9) -(7)

...11y = 11 . . . . . simplify

... y = 1 . . . . . . divide by 11

Using the second equation to find x, we have ...

... x + 4·1 = 9

... x = 5 . . . . . subtract 4

_____

<u>Check</u>

2·5 -3·1 = 10 -3 = 7 . . . . agrees with the first equation

(Since we used the second equation to find x, we know it will check.)

5 0
4 years ago
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The equation for line j can be written as y= 1 2 x–4. Parallel to line j is line k, which passes through the point ( – 8, – 5).
blagie [28]
Just like this
Y=12x+91

8 0
3 years ago
A new fertilizer was applied to the soil of 146 bean plants. 23% showed increased growth. Find the margin of error and 95% confi
USPshnik [31]

Answer:

The significance level for this case would be \alpha=1-0.95=0.05 and the critical value for this case would be:

z_{\alpha/2}=1.96

The margin of error is given by:

ME = z_{\alpha/2} \sqrt{\frac{\hat p (1-\hat p)}{n}}

And replacing we got:

ME = 1.96 \sqrt{\frac{0.23*(1-0.23)}{146}} =0.0683

And the margin of error for this case would be ME = 0.07

Step-by-step explanation:

For this case we have the following dataset given:

n= 146 represent the sample size

\hat p =0.23 represent the estimated proportion of interest

Conf=0.95 represent the confidence level

The significance level for this case would be \alpha=1-0.95=0.05 and the critical value for this case would be:

z_{\alpha/2}=1.96

The margin of error is given by:

ME = z_{\alpha/2} \sqrt{\frac{\hat p (1-\hat p)}{n}}

And replacing we got:

ME = 1.96 \sqrt{\frac{0.23*(1-0.23)}{146}} =0.0683

And the margin of error for this case would be ME = 0.07

4 0
3 years ago
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