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3 years ago

Find the measure of line f and g

Mathematics

1 answer:

kiruha [24]3 years ago

6 0

In this case we use intersecting secant theorem

According to this theorem, GF*GE = GH*GA

So,we plug in the values

(x-3)*(x-3+9) =(x-2)*(x-2+6)

(x-3)*(x+6) =(x-2)*(x+4)

x^2 +6x -3x -18 =x^2 +4x -2x -8

x^2 +3x -18 =x^2 +2x -8

x^2 +3x -18 -x^2 -2x +8 =0

x -10 =0

x=10

So,FG =x-3 = 10-3 =7

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9. Determine whether (-3,2) is a solution of Y = 2x +8 Y= -X+1

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3 years ago

Write an equation of a line in slope-intercept form that passes through (-3,5) and is parallel to y = -6x +1.

katrin2010 [14]

Answer:

a) The equation of the Parallel line to the given straight line is

6 x + y + 13 =0

b) Slope - intercept form

y = - 6 x - 13

c) The intercept - form

$\frac{x}{\frac{-13}{6} } + \frac{y}{-13} = 1$

x - intercept = $\frac{-13}{6}$

y - intercept = - 13

Step-by-step explanation:

Step(i):-

Given the equation of the straight line

y = -6x +1

6 x + y - 1 = 0

The equation of the Parallel line to the given straight line is

6x + y + k=0 and it passes through the point (-3, 5 )

⇒ 6 (-3 ) + 5 + k =0

⇒ - 18 + 5 + k=0

⇒ -13 + k = 0

⇒ k = 13

The equation of the Parallel line to the given straight line is

6 x + y + 13 =0

Step(ii):-

Slope - intercept form

y = m x + C

y = - 6 x - 13

Step(iii):-

Intercept - form

6 x + y + 13 =0

6 x + y = - 13

$\frac{6x + y}{-13} = \frac{-13}{-13}$

$\frac{6x}{-13} + \frac{y}{-13} = 1$

$\frac{x}{\frac{-13}{6} } + \frac{y}{-13} = 1$

The intercept - form

$\frac{x}{\frac{-13}{6} } + \frac{y}{-13} = 1$

x - intercept = $\frac{-13}{6}$

y - intercept = - 13

4 0

3 years ago